Answer:
d = 0.93 g/cm³
Explanation:
Given data:
Mass of object = 28 g
Volume of object = 3cm×2cm×5cm
density of object = ?
Solution:
Volume of object = 3cm × 2cm ×5cm
Volume of object = 30 cm³
Density of object:
d = m/v
by putting values,
d = 28 g/ 30 cm³
d = 0.93 g/cm³
A rock is definitely more dense. If you were to put a cloud in water it would float/stay above it and a rock would sink to the bottom
0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n = ![\frac{PV}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7BPV%7D%7BRT%7D)
putting the values in the equation:
n = ![\frac{1X2}{0.08201 X 273}](https://tex.z-dn.net/?f=%5Cfrac%7B1X2%7D%7B0.08201%20X%20273%7D)
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.