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frozen [14]
3 years ago
14

How are salinity, temperature and circulation related?

Chemistry
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

Salinity, along with temperature, determines the density of seawater, and hence its vertical flow patterns in thermohaline circulation. 2. Salinity records the physical processes affecting a water mass when it was last at the surface. Hope this helps!

Explanation:

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Please answer the attachment below
ipn [44]

Explanation:

population of geese = 1000

number of males in first year = 400 = (400/1000)x100 = 40%

number of males in second year = 500 = (500/1000)x100 = 50%

10% more of the male population is compared with one year ago.

6 0
3 years ago
All of the following are possible sources of error in a scientific investigation except for
lukranit [14]
The answer to this question should be 3. <span>adding research resources during an investigation 
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The answer 1 and 2 are similar. Discovering a new variable mean that you wouldn't control it at the beginning of the research. It would be too late if you try to control it. Incorrect measurement definitely will cause an error.


5 0
3 years ago
Read 2 more answers
What is the half life of an atom that goes from 16000 g to 125 g in 163.24 days.
Alenkinab [10]

Answer:

23.32\ \text{days}

Explanation:

N = Final mass of atom = 125 g

N_0 = Initial mass of atom = 16000 g

t = Time taken = 163.24 days

t_{1/2} = Half life

We have the relation

N=N_0\dfrac{1}{2}^{\dfrac{t}{t_{1/2}}}\\\Rightarrow 125=16000\times \dfrac{1}{2}^{\dfrac{163.24}{t_{1/2}}}\\\Rightarrow \dfrac{125}{16000}=\dfrac{1}{2}^{\dfrac{163.24}{t_{1/2}}}\\\Rightarrow \ln0.0078125=\dfrac{163.24}{t_{1/2}}\ln0.5\\\Rightarrow t_{1/2}=\dfrac{163.24\times\ln0.5}{\ln0.0078125}\\\Rightarrow t_{1/2}=23.32\ \text{days}

The half life of the atom is 23.32\ \text{days}.

3 0
3 years ago
Writing net ionic equation:<br> of cu with nitric acid
Lesechka [4]

The net ionic equation is

Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Molecular equation :</em>

Cu(s) + 4HNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Ionic equation: </em>

Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Net ionic equation </em>

Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)

<em>Note</em>: The net ionic equation is <em>the same as </em>the ionic equation because there are <em>no common ions</em> to cancel on opposite sides of the arrow.

3 0
3 years ago
Now molecules<br> molecules of H,<br> molecules of 02<br> " molecules of H2O
rjkz [21]

Answer:

what is your question?

7 0
4 years ago
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