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3 years ago

How does fabric softener affect the flammability of different fabrics?

1 answer:

5 0

<span>Research shows that fabric softeners decrease flame resistance. The flame resistance of a fabric can be increased in a variety of ways. Most often, the fabric is treated with special flame resistant chemicals. Synthetic fabrics, such as polyester, are naturally flame resistant. These fabrics have a property called thermoplasticity, where the fabric naturally melts and shrinks when exposed to flame. This prevents these fabrics from igniting and burning as easily as other fabrics. Basic properties of a fabric, such as porosity, can also influence flame resistance. Larger pores allow for oxygen to be more present in the fabric, making it more flammable.</span>

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To produce an electric current, you need a continuous source of _________.

Liono4ka [1.6K]

Watts........ or potential diffrence

6 0

3 years ago

Read 2 more answers

How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?

Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

$pH= -log[H]\\pH= -log (\frac{kw}{[OH]})$

$8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}$

$[OH]=1.69E-6$

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

$Cu(OH)_2 -> Cu^{2+} + 2OH^-$

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

$Kps= [Cu^{2+}] [OH]^2$

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

$Kps= s*(2s+1.69E-6)^2$

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is $s=4.96E-8 mol/L$

Now, let us calculate the moles in 1 L:

$moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles$

7 0

3 years ago

A company desires to produce nickel from refining nickel oxide and sulfide ores. the first step of the process will produce a ni

inn [45]

Answer is: increase the concentration of NiCO₄ and <span>withdraw CO from the products as it is forming.

Balanced chemical reaction: NiCO</span>₄(g) ⇄ Ni(s) + 4CO(g).
According to Le Chatelier's Principle the position of equilibrium moves to counteract the change:
1) the position of equilibrium will move to the right, so that the concentration of nickel carbonyl gas decreases again and produce more nickel.
2) the position of equilibrium will move to the right, if we decrease concentration of carbon monoxide, more nickel carbonyl gas will decompose and produce more nickel.

4 0

2 years ago

True or false? The formation of a new state of matter is evidence of a chemical reaction

Snezhnost [94]

Answer: true

Explanation: i think its true

4 0

2 years ago

Which of these four elements is the most reactive metal?

Gala2k [10]

Answer:

Sodium is most reactive metal among these. Sodium is present in group one. It is alkali metal.

Explanation:

Please mark as brainliest

3 0

2 years ago