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miss Akunina [59]
2 years ago
15

What is the wavelength of an AM radio wave in a vacuum if its frequency is 810 kHz?

Physics
1 answer:
dalvyx [7]2 years ago
6 0
Answer- 370.114 meters
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A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 21.0 N/m. The
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Answer:

Explanation:

Force constant of spring K = 21 N /m

we shall find the common velocity of putty-block system from law of conservation of momentum .

Initial momentum of putty

= 5.3 x 10⁻² x 8.97

= 47.54 x 10⁻² kg m/s

If common velocity after collision be V

47.54 x 10⁻² = ( 5.3x 10⁻² + .454) x V

V = .937 m/s

If x be compression on hitting the putty

1/2 k x² = 1/2 m V²

21 x² = ( 5.3x 10⁻² + .454) x .937²

x² = .0212

x = .1456 m

14.56 cm

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Answer:

the following image will make you understand

Explanation:

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3 years ago
Elastic potential energy depends on the amount of ___________ or ___________.
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Which of these is outside of the solar system? sun Saturn galaxy moon
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A charge of 50 µC is pushed by a force of 25 µN a distance of 15 m in an electric field. What is the electric potential differen
sineoko [7]

The electric potential difference is 7.5 V.

Electric potential difference between two points is defined as the work done in moving unit positive charge between the two points. Electric potential difference can also be defined as the work done W per unit charge q in an electric field.

\Delta V=\frac{W}{q}......(1)

Work done by a force is the product of the force F and the displacement s made in the direction of the force. Assuming that the displacement is parallel to the line of action of the force,

W=F.s......(2)

Rewrite equation (1) using equation (2).

\Delta V=\frac{Fs}{q}......(3)

Substitute the given values of force, displacement and charge in the equation (3).

\Delta V=\frac{Fs}{q}\\ =\frac{(25*10^-^6N)(15m)}{(50*10^-^6C)} \\ =7.5V

The potential difference between the two points is 7.5 V


6 0
3 years ago
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