To solve the problem it is necessary to apply energy conservation.
By definition we know that kinetic energy is equal to potential energy, therefore
PE = KE
Where,
m = mass
g = gravitaty constat
v = velocity
h = height
Re-arrange to find h,
Replacing with our values
Therefore the correct answer is C.
Answer:
31.8 × 10⁻⁴ J = 3.18 mJ
Explanation:
We know the intensity I of a wave is I = P/A where P = power and A = area = 0.500 m²
The intensity of an electromagnetic wave is also equal to I = E₀²/μ₀c
where E₀ = maximum electric field strength = √2E where E = rms value of electric field = 0.0200 N/C, μ₀ = 4π × 10⁻⁷ H/m ,c = 3 × 10⁸ m/s
P/A = E₀²/μ₀c = 2E²/μ₀c
P = 2E²A/μ₀c = 2 × (0.02 N/C)² × 0.5 m²/(4π × 10⁻⁷ H/m × 3 × 10⁸ m/s)
= 1.06 × 10⁻⁴ W = 0.106 mW
Since P = E/t where E = Energy and t = time
E = Pt with t = 30 s
E = 1.06 × 10⁻⁴ W × 30 s = 31.8 × 10⁻⁴ J = 3.18 mJ
So the wave carries 3.18 mJ of energy through the window in 30 s
Answer: 8.8e-3 rad/s², 0.0 m/s²
Explanation:
R = 35 / 2 = 17.5 m
a = 2.3 m/s / 15 s = 0.1533333... m/s²
α = a/R = 0.1533333/17.5 = 0.0087619... ≈ 8.8e-3 rad/s² ◄(a)
at maximum speed, no more acceleration in either tangential or angular
α = a = 0.0 rad/s² or m/s² ◄(b)
Explanation:
Option D all of the above
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