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svetoff [14.1K]
4 years ago
11

s it possible for a system to have negative potential energy? Is it possible for a system to have negative potential energy? No,

because the kinetic energy of a system must equal its potential energy. Yes, as long as the total energy is positive. Yes, since the choice of the zero of potential energy is arbitrary. No, because this would have no physical meaning. Yes, as long as the kinetic energy is positive.
Physics
1 answer:
frez [133]4 years ago
8 0

Answer: Yes it possible for a system to have negative potential energy, since the choice of the zero of potential energy is arbitrary.

Explanation:

Potential energy is defined as the energy present in an object due to its position.

Mathematically,   P.E = mgh

A potential energy can be negative also. This is because zero potential energy is arbitrary. For example, at the top of a building the choice of potential energy can be zero.

Therefore, the potential energy below the building will be negative.

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The x-coordinates of two objects moving along the x-axis are given as a function of time (t). x1= (4m/s)t x2= -(161m) + (48m/s)t
Kitty [74]
The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s

The distance between the two objects is
x = x₁ - x₂
   =  4t + 161 - 48t + 4t²
x = 4t² - 44t + 161

Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
  = 4[ (t - 5.5)² - 5.5² ] + 161
 x = 4(t-5)² + 40

Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.

Answer: The distance of the closest approach is 40 m.

5 0
3 years ago
Calculate the inhomogeneity of a 1.5 t magnet
Ludmilka [50]
Need more answer choices
6 0
3 years ago
Which of the following devices could be used to create a position--time graph for an object? 
pickupchik [31]
D none of the above

all of them is related to energy and motion , not to positioning.
6 0
4 years ago
At constant volume, the heat of combustion of a particular compound is − 3550.0 kJ / mol. When 1.075 g of this compound ( molar
swat32

Answer:

C=1,25\cdot 10^{5} kJ/^{\circ}C

Explanation:

First of all let's define the specific molar heat capacity.

C = \frac{-Q}{n\cdot \Delta T} (1)

Where:

Q is the released heat by the system

n is the number of moles

ΔT is the difference of temperature of the system  

Now, we can find n with the molar mass (M) the mass of the compound (m).

n=\frac{m}{M}=6.95\cdot 10^{-3} moles      

Using (1) we have:

C=\frac{-3550}{6.95\cdot 10^{-3} 4.073}

C=1,25\cdot 10^{5} kJ/^{\circ}C

I hope it helps!

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4 years ago
I'm a given chemical reaction, the energy of the products is less than the energy of the reactants. Which statement is true for
garik1379 [7]
The answer would have to be D.
8 0
3 years ago
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