Answer:
11025 N / m²
Explanation:
Los siguientes datos se obtuvieron de la pregunta:
Área (A) = 400 cm²
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Presión (P) =?
A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Fuerza (F) =.?
F = m × g
F = 45 × 9,8
F = 441 N
A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:
1 cm² = 0,0001 m²
Por lo tanto,
400 cm² = 400 cm² × 0,0001 m² / 1 cm²
400 cm² = 0,04 m²
Por tanto, 400 cm² equivalen a 0,04 m².
Finalmente, determinaremos la presión ejercida de la siguiente manera:
Área (A) = 0.04 m².
Fuerza (F) = 441 N
Presión (P) =?
P = F / A
P = 441 / 0,04
P = 11025 N / m²
Por tanto, la presión ejercida es 11025 M / m²
It can be explained as follows: consider the field produced by a positive charge. If we place a positive test charge in this a field, then this charge would move away from the central charge (because like charges repel), while if we place a negative test charge in this field, this charge would move towards the central charge (because opposite charges repel)
Explanation:
Electric fields are vector fields, and they are represented using field lines.
The field lines give indications on both the magnitude and the direction of the electric field. In fact:
- The magnitude of the field can be inferred from the spacing between the lines: the closer the lines are, the stronger the field, while for a weaker field the lines are more spread apart
- The direction of the field is given by the direction of the field lines
In particular, by convention the direction of the field lines represent the direction of the force that a positive test charge would feel when immersed in that field: this means that a positive test charge would accelerate in the direction of the field lines, while a negative test charge would accelerate in the direction opposite to the field lines.
This is in agreement with the fact that like charges repel and opposite charges attract. In fact, the lines of the electric field produced by a single-point positive charge point away from the positive charge: if we place a positive test charge in this field, then this charge would move away from the central charge (because like charges repel), while if we place a negative test charge in this field, this charge would move towards the central charge (because opposite charges repel).
Learn more about electric fields:
brainly.com/question/8960054
brainly.com/question/4273177
#LearnwithBrainly
Answer:
Q = 836.4 Joules.
Explanation:
Given the following data;
Mass = 100 grams
Initial temperature = 25°C
Final temperature = 45°C
We know that the specific heat capacity of water is equal to 4.182 J/g°C.
To find the quantity of heat;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 45 - 25
dt = 20°C
Substituting the values into the equation, we have;
Q = 836.4 Joules.
Answer:
Explanation:
Change in length of spring = 2.13 m
Component of weight acting on spring = mg sinθ
so
mg sinθ = k x where k is spring constant and x is total stretch due to force on the spring.
Here x = 2.13
mg sin17 = k x 2.13
31 x 9.8 sin17 = k x 2.13
k = 41.7 N/m
b ) In case surface had friction , spring would have stretched by less distance .
It is so because , the work done by gravity in stretching down is stored as potential energy in spring . In case of dissipative force like friction , it also takes up some energy in the form of heat etc so spring stretches less.
Answer:
Second option 6.3 N at 162° counterclockwise from
F1->
Explanation:
Observe the attached image. We must calculate the sum of all the forces in the direction x and in the direction y and equal the sum of the forces to 0.
For the address x we have:

For the address and we have:

The forces
and
are known

We have 2 unknowns (
and b) and we have 2 equations.
Now we clear
from the second equation and introduce it into the first equation.

Then

Then we find the value of 

Finally the answer is 6.3 N at 162° counterclockwise from
F1->