1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fredd [130]
3 years ago
5

Assuming ideal solution behavior, what is the freezing point of a solution of 9.04 g of I2 in 75.5 g of benzene?

Chemistry
1 answer:
cluponka [151]3 years ago
3 0

Answer:

3.1°C

Explanation:

Using freezing point depression expression:

ΔT = Kf×m×i

<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>

Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:

9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m

Replacing in freezing point depression formula:

ΔT = 5.12°cm⁻¹×0.472m×1

ΔT = 2.4°C

As freezing point of benzene is 5.5°C, the new freezing point of the solution is:

5.5°C - 2.4°C =

<h3>3.1°C</h3>

<em />

You might be interested in
Draw the product of the reaction between CH3CH=CHCH3 and H2 under a platinum catalyst.
Pani-rosa [81]

Answer:

CH₃CH₂-CH₂CH₃

Explanation:

When an alkene, R-CH=CH-R reacts with H₂ in a Pt catalyst, the analogue alkane, R-CH₂-CH₂-R, is produced (Hydrogenation of alkenes via Pt/Pd catalyst)

Thus, the reaction of CH₃CH=CHCH₃ with H₂ under a platinum catalyst produce:

<h3>CH₃CH₂-CH₂CH₃</h3>

The analogue alkane

4 0
3 years ago
PLEEASE HELP TIMED WILL GIVE BRAINLIEST TO CORRECT ANSWER NLY PLEASEEEE HELPPPP
Arturiano [62]

Answer:

1) 1.15 mol

2) M=0.45

3) 22.5 mL

4) 6.25 mL

Explanation:

1)

550 mL= 0.55 L

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (2.1 M * 0.55 L )        M=1.15 mol solute

2)

155 mL = 0.155 L

80 g  -> 1 mol NH4NO3

5.61 g -> x

x= (5.61 g * 1 mol NH4NO3)/80 g       x= 0.07 mol NH4NO3

M=(0.07 mol NH4NO3)/0.155 L         M=0.45

3) M1V1=M2V2

V1= M2V2/M1

V1= (0.500 M * 0.225 L)/5.00 M             V1=0.0225 L =22.5 mL

4) M1V1=M2V2

V1= M2V2/M1

V1= (0.25 M * 0.45 L)/ 18.0 M

V1=6.25 x 10^-3 L = 6.25 mL

8 0
3 years ago
Read 2 more answers
Billy beaker traveled 115 kilometers in one morning: how far is this in feet
Pachacha [2.7K]
Is the answer youre looking for 377297 feet
8 0
3 years ago
Read 2 more answers
The molecule I2 has a lower melting point than Cl2.<br><br> TRUE<br><br> FALSE
Gala2k [10]
True. <span><span>Melting points decrease down a group and increase across a period.</span> </span>
3 0
3 years ago
Read 2 more answers
Please help me!! Look at the picture to understand the question please!
Romashka-Z-Leto [24]

Answer:

C. I

Explanation:

The elements are categorized in groups and periods. The periods are horizontal and the groups are vertical. The elements in the same group (vertical) have very similar characteristics.

5 0
3 years ago
Other questions:
  • What information is needed to calculate the ph of a solution?
    8·1 answer
  • What is the mass of 3.75 moles of NaCl
    6·2 answers
  • Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na
    5·2 answers
  • List some of the important biological functions of carbohydrates
    10·1 answer
  • PLEASEE HELPP MEEE WITH NUMBER 5!!!!!!<br> please explain why!!!!
    8·1 answer
  • Which type of heat transfer causes a person sitting by the fire to feel warm
    9·2 answers
  • How many grams are in 6.02E23 atoms of carbon?
    13·1 answer
  • Indica las condiciones que debe cumplir una colisión entre moléculas para que se produzca una reacción química
    6·1 answer
  • What happens to the sugar from a sugar cube after it has dissolved in a cup of tea? (Molecule related)​
    13·2 answers
  • Which of the following reactions would you find in a radioisotope thermal generator?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!