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wariber [46]
3 years ago
9

How many total atoms are in 0.670 g of p2o5?

Chemistry
1 answer:
scoray [572]3 years ago
8 0

The molecular formula for compound is  P_{2}O_{5} mass of compound is 0.670 g.

To calculate number of atoms first calculate number of moles in the compound as follows:

n=\frac{m}{M}

Molar mass of  P_{2}O_{5} is 283.886 g/mol, thus,

n=\frac{0.670 g}{283.886 g/mol}=0.00236 mol

Thus, number of mole of P_{2}O_{5} is 0.00236 mol.

From the molecular formula 1 mole of P_{2}O_{5} has 2 mol of P (phosphorus) and 5 mol of O (oxygen).

Thus, number of moles of P and O in 0.00236 mol of P_{2}O_{5} will be:

n_{P}=2\times 0.00236 mol=0.00472 mol

Similarly,

n_{O}=5\times 0.00236 mol=0.0118 mol

Now, in 1 mol of an element there are 6.023\times 10^{23} atoms.

Number of atoms of P will be:

N_{P}=0.00472\times 6.023\times 10^{23}=2.84\times 10^{21}atoms

Similarly, number of atoms of O will be:

N_{O}=0.0118\times 6.023\times 10^{23}=7.11\times 10^{21}atoms

Total number of atoms will be sum of number of atoms of P and O:

N_{Total}=N_{P}+N_{O}=2.84\times 10^{21}+7.11\times 10^{21}=9.95\times 10^{21} atoms

Therefore, total number of atoms in P_{2}O_{5} will be 9.95\times 10^{21} atoms.

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