This is an oxidation-reduction (redox) reaction:
2 Mg0 - 4 e- → 2 MgII
(oxidation)
2 O0 + 4 e- → 2 O-II
(reduction)
Answer:
C. 2.4 M
Explanation:
Because you started with 12M solution of KCl, that means that there was a concentration of 12 mols of KCl per Liter of solution. (12mol/1L =12 M). Since there was only 0.5L of solution, there was only 6 mols of KCl because there is only 12 mols per 1 Liter, so half of that volume would have half the amount of solute to keep that true. (6mol/.5L = 12 M). With the new water added, the formula becomes (6mols KCl/ 2.5L of water =2.4 M)
I guess the answer is MgO4S
Answer:
A = Ureter
- Small amounts of urine flow from the ureters into the bladder
B = Urethra
- The Urethra is the tube that carries urine from the bladder to outside the body
C = Urinary Bladder
D = Kidney
- remove wastes and extra fluid from your body.
<u>-TheUnknown</u><u>Scientist</u>