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45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)
The balanced equation for the reaction is given below:
2Al + 3Cl₂ —> 2AlCl₃
From the balanced equation above,
2 atoms of Al required 3 molecules of Cl₂.
With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:
From the balanced equation above,
2 atoms of Al required 3 molecules of Cl₂.
Therefore,
30 atoms of Al will require = = 45 molecules of Cl₂.
Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)
Learn more: brainly.com/question/24918379
Answer : The volume of solution required is, 2.93 L
The number of moles of formed from the reaction is, 0.662 moles.
Explanation :
First we have to calculate the initial moles of .
Now we have to calculate the moles of
The balanced chemical reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of react with 2 moles of
So, 0.662 mole of react with
moles of
Now we have to calculate the volume of
Now we have to calculate the moles of
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 1 moles of
So, 0.662 mole of react to give 0.662 moles of
Thus, the number of moles of formed from the reaction is, 0.662 moles.