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erma4kov [3.2K]
3 years ago
7

Which of these objects in the solar system have impact craters. The Moon Earth Mars

Chemistry
2 answers:
Reika [66]3 years ago
4 0

the moon because it's the closest

Vaselesa [24]3 years ago
3 0

Answer: The moon

Explanation: hope this helps.

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Calculate the density of the items below. (D = M/V)<br> 1) M = 15g V = 5.0ml *
grin007 [14]

Answer:

<h3>The answer is 3.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 15 g

volume = 5 mL

We have

density =  \frac{15}{5}  \\

We have the final answer as

<h3>3.0 g/mL</h3>

Hope this helps you

5 0
3 years ago
A series circuit has two 5.0-ohm resistors and a power source of 9.0 volts. How will the current be affected and what will it be
miskamm [114]
The formula for solving current given with resistance and power source or voltage is shown below:
I = V/R  

When two 5 ohms resistors are in series, we have:
I = 9 volts / (5+5 ohms)
I = 0.9 amperes

When it is being added with another 7.5 resistors, we have:
I = 9 volts / (5+5+7.5 ohms)
I = 0.529 ampere

The answer to the question is the letter "D. decrease; 0.51 amps".
3 0
4 years ago
A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
lidiya [134]

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

3 0
3 years ago
Calculate the acid dissociation constant Ka of a 0.2 M solution of weak acid that is 0.1% ionized is ________.
mars1129 [50]

Answer: acid dissociation constant Ka= 2.00×10^-7

Explanation:

For the reaction

HA + H20. ----> H3O+ A-

Initially: C. 0. 0

After : C-Cx. Cx. Cx

Ka= [H3O+][A-]/[HA]

Ka= Cx × Cx/C-Cx

Ka= C²X²/C(1-x)

Ka= Cx²/1-x

Where x is degree of dissociation = 0.1% = 0.001 and c is the concentration =0.2

Ka= 0.2(0.001²)/(1-0.001)

Ka= 2.00×10^-7

Therefore the dissociation constant is

2.00×10^-7

7 0
3 years ago
When the moon appears larger than 1/2 but less than full
Diano4ka-milaya [45]
It is called a waxxing gibbous, pls brainliest
5 0
3 years ago
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