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Stells [14]
3 years ago
13

Edgar was given four substances to mix together. The table shows the densities of the four substances. List the order in which E

dgar would see the four substances separate, starting with the substance on the top layer to the substance on the bottom layer of the beaker.
A. Honey, water, olive oil, ethyl alcohol

B. Water, olive oil, honey, ethyl alcohol

C. Olive oil, ethyl alcohol, honey, water

D. Ethyl alcohol, olive oil, water, honey

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:D

Explanation:

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Si una masa dada de hidrógeno ocupa 40 litros a 700 grados torr. ¿Qué volumen ocupará a 1 atmósfera de presión? (dar la presión
Svetach [21]

Answer:

V_2=36.84L

Explanation:

Hola,

En este caso, podemos usar la ley de Boyle, la cual nos permite analizar el comportamiento volumen-presión en un gas ideal de manera inversamente propocional:

P_1V_1=P_2V_2

Así, dado el volumen y la presión inicial, la cual se convierte a atmósferas (760 torr = 1atm), calculamos el volumen final a 1 atm como se muestra a continuación:

V_2=\frac{P_1V_1}{P_2}=\frac{700torr*\frac{1atm}{760torr}*40l }{1atm}\\  \\V_2=36.84L

Saludos!

7 0
3 years ago
Read 2 more answers
Consider the following Reaction.
jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol


number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 =>  0.5246 moles

Molar mass of H3PO4 =  97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:


3 Mg(OH)2 + 2 H3PO4 --->  Mg3(PO4)2 + 6 H2O


3 mol of Mg(OH)2 reacts with 2 mol of H3PO4  ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation  .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation  :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2


= (1/3)*0.5246


= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass


= 0.1749 *  262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%


Hope that helps!




3 0
3 years ago
Question: complete the mechanism for the below oxidation of an alkene with kmno4. draw the missing curved
iren2701 [21]

Mechanism for oxidation of alkene by KMnO₄ is provided in the attached image:

6 0
3 years ago
In the diagram, what is happening to the ENERGY during Segment C? Phase Change Diagram_Water Question 16 options: The kinetic en
Leviafan [203]

There was an increase in kinetic energy during the segment C and in other segments

Recall: That temperature is a measure of the average kinetic energy, so increasing temperature all cause increasing kinetic energy and vice versa.

However too, the heat energy which is added during the phase change is usually used to overcome forces in order to hold the molecules together.

<h3>What is kinetic energy?</h3>

Kinetic energy is the type of energy an object or a body posesss due to it motion

The body usually maintains it's kinetic energy unless the speed changes

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4 0
3 years ago
Name:
Liono4ka [1.6K]

Answer:

1. 505g is the mass of the aluminium.

2. The answer is in the explanation

Explanation:

1. To solve this question we need to find the volume of the rectangle. With the volume and density we can find the mass of the solid:

Volume = 7.45cm*4.78cm*5.25cm

Volume = 187cm³

Mass:

187cm³ * (2.702g/cm³) = 505g is the mass of the aluminium

2. When the temperature of a liquid increases, the volume increases doing the density decreases because density is inversely proportional to volume. And works in the same way for gases because the temperature produce more collisions and the increasing in volume.

4 0
3 years ago
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