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lyudmila [28]
1 year ago
10

Xenon-135 is produced in a nuclear reactor by two primary methods. one is directly from fission, the other is from the decay of:

_______
Chemistry
1 answer:
LekaFEV [45]1 year ago
6 0

Xenon-135 is produced from the  the decay of iodine-135.

<h3>What is a nuclear reactor?</h3>

The term nuclear reactor refers to an instrument where nuclear reaction takes place. Now we know that nuclear reactions can be used for several purposes and one of those purposes is the generation of electricity.

Now, Xenon-135 is produced in a nuclear reactor by two primary methods. one is directly from fission, the other is from the decay of iodine-135.

Learn more about nuclear reactor:brainly.com/question/13869748

#SPJ1

Missing parts

Xenon-135 is produced in a reactor by two primary methods. One is directly from fission; the other

is from the decay of...

A. cesium-135.

B. iodine-135.

C. xenon-136.

D. iodine-136.

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Will bromine react with sodium and why?
Archy [21]

<span><span>When you write down the electronic configuration of bromine and sodium, you get this

Na:
Br: </span></span>

<span><span />So here we the know the valence electrons for each;</span>

<span><span>Na:  (2e)
Br:  (7e, you don't count for the d orbitals)

Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.

However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>

<span><span /></span><span><span>

</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>

<span>
</span>

4 0
3 years ago
A chemist adds 0.60L of a 0.20/molL sodium thiosulfate Na2S2O3 solution to a reaction flask. Calculate the millimoles of sodium
Serggg [28]

Answer:

1.2×10² mmole of Na₂S₂O₃

Explanation:

From the question given above, the following data were obtained:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the number of mole of Na₂S₂O₃ in the solution as illustrated below:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity = mole /Volume

0.2 = Mole of Na₂S₂O₃ / 0.6

Cross multiply

Mole of Na₂S₂O₃ = 0.2 × 0.6

Mole of Na₂S₂O₃ = 0.12 mole

Finally, we shall convert 0.12 mole to millimole (mmol). This can be obtained as follow:

1 mole = 1000 mmol

Therefore,

0.12 mole = 0.12 mole × 1000 mmol / 1 mole

0.12 mole = 120 = 1.2×10² mmole

Thus, the chemist added 1.2×10² mmole of Na₂S₂O₃

7 0
3 years ago
If 45 mL of water are added to 250 mL of a 0.75 M K2SO4 solution, what will the molarity of the diluted solution be?
krok68 [10]

Answer:

\large\boxed{\large\boxed{0.64M}}

Explanation:

When you form a <em>diluted solution</em> from a mother (concentrated) solution, the moles of solute are determined by the mother solution.

The main equation is:

Molarity=\dfrac{\text{moles of solute}}{\text{volume of the solution in liters}}

Then, since the moles of solute is the same for both the mother solution and the diluted solution:

          \text{Molarity mother solution }\times\text{ volume mother solution}=\\\\=\text{Molarity diluted solution }\times\text{ volume diluted solution}

Substitute and solve for the molarity of the diluted solution:

           250mL\times 0.75M=(45mL+250mL)\times M\\\\\\M=\dfrac{250mL\times 0.75M}{295mL}=0.64M

8 0
3 years ago
Which of the following organisms would likely be found on a decaying deer carcass (dead deer)?
TEA [102]

Answer:

c. bacteria and fungus

Explanation:

3 0
3 years ago
Read 2 more answers
Think of two organisms.
Alina [70]

DNA is one and Grow and Develop i think i could be wong  let me know i can read up on it some more


4 0
3 years ago
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