Answer:
T = 2.83701481512 seconds
Explanation:
Hi!
The formula that you will want to use to solve this question is:
T--> period
L --> length of the pendulum
g --> acceleration due to gravity (9.8m/s^2)
since we know that the mass of the bob at the end of the pendulum does not affect the period of the pendulum, we can go ahead and ignore that bit of information (unless, of course, the weight causes the pendulum to stretch)
so now we can plug in our given info into the formula above and solve!
T = 2*pi * sqrt(2/9.8)
T = 2.83701481512 seconds
*Note*
- I used 3.14 to pi, if you need to use a different value for pi (a longer version, etc) your answer will be slightly different
I hope this helped!
Everything in presence is moving. That is the most essential naturally visible thing to think about the universe. In this way, consider a youthful star and any sensible measure of material about it. Regardless of the possibility that it was by one means or another equally, arbitrarily separated in a circle about the youthful star and moving in any case, the star and its gravitational impacts will rule. So its immense mass turns in a given plane and its gravity field twists fundamentally spacetime in that plane and less so in whatever another plane. In any case, the development of the star drags the only things that are important around it step by step into its rotational plane.
The distance the ball rolls is given by
<em>x</em> = 1/2 <em>a</em> <em>t</em>²
so that
<em>x</em> = 1/2 * (3.3 m/s²) * (7.5 s)² = 92.8125 m ≈ 93 m
+3 ....>>>>>>>>..... i have added 20 characters to properly explain my answer
:3