Answer:
a) 4 s
b) 36 m/s²
c) 54 m
Explanation:
s = 2t³ – 24t + 6
a) Find t when v = 72 m/s.
v = ds/dt
v = 6t² – 24
72 = 6t² – 24
6t² = 96
t = 4
b) Find a when v = 30 m/s.
a = dv/dt
a = 12t
When v = 30:
30 = 6t² – 24
6t² = 54
t = 3
a = 36
c) Find Δs between t = 1 and t = 4
Δs = (2(4)³ – 24(4) + 6) – (2(1)³ – 24(1) + 6)
Δs = 38 – (-16)
Δs = 54
Answer:
TEJ as this is a thing you wont get
Answer:
Explanation:
By conservation of energy, speed of the ball going up = speed of ball coming down with the ball stops at the top.
Because the gravity acceleration is constant, by symmetry, half of total time, 6/2 = 3s, is for going up and the last 3s for coming down.
Consider the last 3s when the ball drops from top to bottom, the initial velocity = 0 and acceleration = 10m/s^2
distance traveled = initial velocity * time + 1/2 * acceleration * time^2
= 0*3 + 1/2*10*3^2
= 5*9
= 45m
So maximum height of the ball is 45m.
Answer:
The finger has to be placed at 5.25cm
Explanation:
The steps and appropriate formula in musical instrument is as shown in the attachment.
