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Deffense [45]
3 years ago
13

I'll GIVE BRAINLY

Chemistry
1 answer:
kenny6666 [7]3 years ago
8 0

Answer:

Hey there!

35 s represents time.

The s means "seconds."

Let me know if this helps :)

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12.2 scientific notation
Nadya [2.5K]

This would be 1.22 x 10^1

You simply move the decimal.

If this helped you, please list me as brainliest!

3 0
3 years ago
Balance the following chemical equation Na + Cl2 -> NaCl and explain how the balanced equation models the law of conservation
Alexus [3.1K]

Answer:

2 Na + 1 Cl2 -> 2 NaCl

Explanation:

The answer is really simple, because if you have 1 nonmetal element that has a subscript of 2, you need to multiply the product and the first reactant by 2 to balance it.

7 0
3 years ago
Is h3co3 a strong base
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I read and said it's a weak base
3 0
2 years ago
describe the placement of the crucible lid on the crucible when heating the magnesium. Why is it important that this be done cor
Andreas93 [3]
What
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7 0
3 years ago
Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c
jok3333 [9.3K]

Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, Mg = 0.100 mol

Moles of hydrochloric acid, HCl = 0.500 mol

According to the reaction shown below:-

Mg_{(s)} + 2HCl_{(aq)}\rightarrow MgCl_2_{(aq)} + H_2_{(g)}

1 mole of Mg reacts with 2 moles of HCl

0.100 mol of Mg reacts with 2*0.100 mol of HCl

Moles of HCl must react = 0.200 mol

Available moles of HCl = 0.500 moles

Limiting reagent is the one which is present in small amount. Thus, Mg is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of Mg on reaction forms 1 mole of H_2

0.100 mole of Mg on reaction forms 0.100 mole of H_2

Mole of H_2 = 0.100 mol

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Volume = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K  

<u>⇒V = 2.24 L</u>

2.24 L of hydrogen gas, measured at STP, are produced.

4 0
3 years ago
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