Suppose a scientist conducts a series of experiments and the results are so amazing she wants to share them with other experts i
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Hi there!
We can use Biot-Savart's Law for a moving particle:
B = Magnetic field strength (T)
v = velocity of electron (0.130c = 3.9 × 10⁷ m/s)
q = charge of particle (1.6 × 10⁻¹⁹ C)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
r = distance from particle (2.10 μm)
There is a cross product between the velocity vector and the radius vector (not a quantity, but specifies a direction). We can write this as:
Where 'θ' is the angle between the velocity and radius vectors.
a)
To find the angle between the velocity and radius vector, we find the complementary angle:
θ = 90° - 60° = 30°
Plugging 'θ' into the equation along with our other values:
b)
Repeat the same process. The angle between the velocity and radius vector is 150°, and its sine value is the same as that of sin(30°). So, the particle's produced field will be the same as that of part A.
c)
In this instance, the radius vector and the velocity vector are perpendicular so
'θ' = 90°.
d)
This point is ALONG the velocity vector, so there is no magnetic field produced at this point.
Aka, the radius and velocity vectors are parallel, and since sin(0) = 0, there is no magnetic field at this point.
Answer:
The angle between the blue beam and the red beam in the acrylic block is
Explanation:
From the question we are told that
The refractive index of the transparent acrylic plastic for blue light is
The wavelength of the blue light is
The refractive index of the transparent acrylic plastic for red light is
The wavelength of the red light is
The incidence angle is
Generally from Snell's law the angle of refraction of the blue light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
The angle between the blue beam and the red beam in the acrylic block
substituting values