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Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
Explanation:
Given: = 237 K,
= 101.33 kPa,
= ?
= 300 K,
= 151.99 kPa,
= 0.50 L
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.