Question

Last question: pleaseee help :/

Answer 1

I believe the correct answer from the choices listed above is option D. The amplitude, period, and frequency of the motion of the mass are given by amplitude = 3, period = , and frequency = 2. The standard form of this model would be as follows:

y = A sin Bx

where A is the amplitude and 2pi/B is the period. Frequency is the reciprocal of the period. Hope this answers the question. Have a nice day.

Answer 2

Answer:

The amplitude is 3, the time period is 0.5 and the frequency is 2.

D is correct.

Explanation:

Given that,

$y = 3 sin(4)(\pi)(t)$

We know that,

The general equation of the S.H.M

$y = A\ sin\omega\ t$

Where, y = displacement

A = amplitude

According to equation,

Amplitude = 3

The frequency is

Frequency $\omega = 2\pi f$

$4\pi=2\pi f$

$f = 2$

The time period is reciprocal of frequency.

$T = \dfrac{1}{f}$

$T =\dfrac{1}{2}$

$T = 0.5$

Hence, The amplitude is 3, the time period is 0.5 and the frequency is 2.