C is the slowest of the runners, but starts at a position ahead of A and B when the starting gun is fired, so C is in the lead for a while.
A and B both start from the starting line when the starting gun is fired. A is faster than B. So A is the first to pass C, and A stays in the lead after that.
After a short while, B also passes C.
After that, C remains last on the track.
Answer:
Ein: 2.75*10^-3 N/C
Explanation:
The induced electric field can be calculated by using the following path integral:
![\int E_{in} dl=-\frac{\Phi_B}{dt}](https://tex.z-dn.net/?f=%5Cint%20E_%7Bin%7D%20dl%3D-%5Cfrac%7B%5CPhi_B%7D%7Bdt%7D)
Where:
dl: diferencial of circumference of the ring
circumference of the ring = 2πr = 2π(5.00/2)=15.70cm = 0.157 m
ФB: magnetic flux = AB (A: area of the loop = πr^2 = 1.96*10^-3 m^2)
The electric field is always parallel to the dl vector. Then you have:
![E_{in}\int dl=E_{in}(2\pi r)=E_{in}(0.157m)](https://tex.z-dn.net/?f=E_%7Bin%7D%5Cint%20dl%3DE_%7Bin%7D%282%5Cpi%20r%29%3DE_%7Bin%7D%280.157m%29)
Next, you take into account that the area of the ring is constant and that dB/dt = - 0.220T/s. Thus, you obtain:
![E_{in}(0.157m)=-A\frac{dB}{dt}=-(1.96*10^{-3}m^2)(-0.220T/s)=4.31*10^{-4}m^2T/s\\\\E_{in}=\frac{4.31*10^{-4}m^2T/s}{0.157m}=2.75*10^{-3}\frac{N}{C}](https://tex.z-dn.net/?f=E_%7Bin%7D%280.157m%29%3D-A%5Cfrac%7BdB%7D%7Bdt%7D%3D-%281.96%2A10%5E%7B-3%7Dm%5E2%29%28-0.220T%2Fs%29%3D4.31%2A10%5E%7B-4%7Dm%5E2T%2Fs%5C%5C%5C%5CE_%7Bin%7D%3D%5Cfrac%7B4.31%2A10%5E%7B-4%7Dm%5E2T%2Fs%7D%7B0.157m%7D%3D2.75%2A10%5E%7B-3%7D%5Cfrac%7BN%7D%7BC%7D)
hence, the induced electric field is 2.75*10^-3 N/C
Galileo discovered during his inclined-plane experiments that a ball rolling down an incline and onto a horizontal surface would roll indefinitely.
Answer:
Initial speed of the spaceship 1, v = 2 m/s
Explanation:
Given that :
Mass of spaceship 1 and 2 that have equal mass are 300 kg
Initial momentum of the spaceship 1 is 600 kg-m/s
To find :
We need to find the initial momentum of spaceship 1.
Solve :
The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :
![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
![v=\dfrac{p}{m}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bp%7D%7Bm%7D)
![v=\dfrac{600\ kg-m/s}{300\ kg}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B600%5C%20kg-m%2Fs%7D%7B300%5C%20kg%7D)
v = 2 m/s
Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.