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denpristay [2]
3 years ago
7

Dallas says that any change in velocity is directly proportional tothe time interval over which the change took place. Dana says

thatis true only when the acceleration is constant. Which one, ifeither, is correct?
a. Dana,because it is true then the acceleration is constant
b. Dallas,because we can define ax, avg so thatDvx= ax, avgt.
c. Dallas,because ax, avg always is equalto
d. Allthe above are correct.
e. Only(a) and (b) above are correct
Physics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

e. Only(a) and (b) above are correct

Explanation:

Impulse

= Fx t = m ( v-u )

v-u = change in velocity

F x t = mass x change in velocity

change in velocity = F t / mass

=a t

change in velocity ∝ t ( time ) , if a is constant

dv = a_avg  dt

∫dv = a_avg ∫dt

v-u = a_avg t

change in velocity ∝ t ( time )

So both (a) and (b) are correct.

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A 1,200 kg dragster, starting from rest, reaches a maximum velocity of 140m/s in 5 seconds. At the 5 second mark, the dragster d
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Les propriétés de l’air?
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two barges full of salted toad guts have a collision. the red barge has a mass of 150000kg and is traveling northwest at 0.25m/s
solniwko [45]

The final velocity of the red barge in the collision elastic is 0.311 m/s when it collides with blue barge pf mass 1000000 kg.

Final velocity(v3)  of the red barge is calculated by following formula

m1×v1+ m2×v2= (m1+m2)v3

Substituting the value of m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s

150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3

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<h3>What is elastic collision velocity? </h3>
  • The velocity of the target particle after a head-on elastic impact in which the projectile is significantly more massive than the target will be roughly double that of the projectile, but the projectile velocity will remain virtually unaltered.

For more information on elastic collision velocity kindly visit to

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6 0
1 year ago
Assume a small 11 kg crate is attached to a parachute. The chute pulls up on the crate with 150 N.
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b. From Newton's second law, the net force equals the mass times acceleration:

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v = 19.2 m/s

3 0
3 years ago
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