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3 years ago

A 4.82L balloon filled with gas is warmed from 243.1K to 300.1 K. What is the volume of the gas after it is heated?

Chemistry

1 answer:

Ksenya-84 [330]3 years ago

5 0

Answer:

5.95 L

Explanation:

V1/V2 = T1/T2

4.82 L/V2 = 243.1K/300.1K

V2 = 4.82*300.1/243.1 L = 5.95 L

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What happens when an oceanic plate collides with a continental plate?

Fynjy0 [20]

What happens when an oceanic plate collides with a continental plate?

C. The oceanic plate moves under the continental plate

6 0

2 years ago

According to the equation, 2 H2 + O2 --> 2 H20, how many moles of oxygen are required to convert 12 moles of hydrogen to wate

DerKrebs [107]

Answer:

6 moles of oxygen, or 3O2.

Explanation:

I would build a proportion for this:

$\frac{2(2)}{2} = \frac{12}{x} \\ 4x = 24 \\ x = 6$

5 0

2 years ago

How many liters of carbon dioxide will be produced at STP if 3.56 g calcium carbonate reacts completely with carbon dioxide? CaC

sp2606 [1]

Answer:

V = 0.798 L

Explanation:

Hello there!

In this case, for this gas stoichiometry problem, we first need to compute the moles of carbon dioxide via stoichiometry and the molar mass of starting calcium carbonate:

$3.56gCaCO_3*\frac{1molCaCO_3}{100gCaCO_3} *\frac{1molCO_2}{1molCaCO_3} =0.0356molCO_2$

Next, we use the ideal gas equation for computing the volume, by bearing to mind that the STP conditions stand for a pressure of 1 atm and a temperature of 273.15 K:

$PV=nRT\\\\V=\frac{nRT}{P}\\\\V=\frac{0.0356mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm} \\\\V=0.798L$

Best regards!

4 0

2 years ago

A 25.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/mol°C) is heated to 86.4°C and dropped into a calorimeter

Ira Lisetskai [31]

Answer:

m H2O = 56 g

Explanation:

Q = mCΔT

∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:

⇒ - (mCΔT)Al = (mCΔT)H2O

∴ m Al = 25.0 g

∴ Mw Al = 26.981 g/mol

⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al

⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C

⇒ Q Al = 1327.64 J

∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C

⇒ mH2O = 55.722 g ≅ 56 g

5 0

2 years ago

A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti

boyakko [2]

The answer is C, 58.6

7 0

3 years ago

Read 2 more answers