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Vaselesa [24]
3 years ago
11

A can, containing only air, has its lid tightly screwed on and is left in strong sunlight

Physics
1 answer:
allsm [11]3 years ago
3 0

Answer:

Because everyone knows that when you increase temperature activity withn molecules increases they will collide more making the can probably explode

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A small cork with an excess charge of +6.0µC is placed 0.12 m from another cork, which carries a charge of -4.3µC.
Volgvan

A) 16.1 N

The magnitude of the electric force between the corks is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 = 6.0 \mu C=6.0 \cdot 10^{-6} C is the magnitude of the charge on the first cork

q_2 = 4.3 \mu C = 4.3 \cdot 10^{-6}C is the magnitude of the charge of the second cork

r = 0.12 m is the separation between the two corks

Substituting numbers into the formula, we find

F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(6.0\cdot 10^{-6}C)(4.3\cdot 10^{-6} C)}{(0.12 m)^2}=16.1 N

B) Attractive

According to Coulomb's law, the direction of the electric force between two charged objects depends on the sign of the charge of the two objects.

In particular, we have:

- if the two objects have charges with same sign (e.g. positive-positive or negative-negative), the force is repulsive

- if the two objects have charges with opposite sign (e.g. positive-negative), the force is attractive

In this problem, we have

Cork 1 has a positive charge

Cork 2 has a negative charge

So, the force between them is attractive.

C) 2.69\cdot 10^{13}

The net charge of the negative cork is

q_2 = -4.3 \cdot 10^{-6}C

We know that the charge of a single electron is

e=-1.6\cdot 10^{-19}C

The net charge on the negative cork is due to the presence of N excess electrons, so we can write

q_2 = Ne

and solving for N, we find the number of excess electrons:

N=\frac{q_2}{e}=\frac{-4.3\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=2.69\cdot 10^{13}

D) 3.75\cdot 10^{13}

The net charge on the positive cork is

q_1 = +6.0\cdot 10^{-6}C

We know that the charge of a single electron is

e=-1.6\cdot 10^{-19}C

The net charge on the positive cork is due to the "absence" of N excess electrons, so we can write

q_1 = -Ne

and solving for N, we find the number of electrons lost by the cork:

N=-\frac{q_1}{e}=-\frac{+6.0\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=3.75\cdot 10^{13}

6 0
3 years ago
El cuerpo de una persona está cubierto con 1.6 m2 de ropa de lana. El grosor de la lana es 2.0 x 10-3 metro. La temperatura en l
netineya [11]

Answer:

<h2>Rate of heat transfer from the body of the person is given as</h2><h2>\frac{dQ}{dt} = 800 J/s</h2>

Explanation:

As we know that the rate of heat transfer due to thermal conduction is given as

\frac{dQ}{dt} = \frac{kA(T_2 - T_1)}{x}

so we have

k = 0.04 W/m C

A = 1.6 m^2

x = 2\times 10^{-3} m

\frac{dQ}{dt} = \frac{(0.04)(1.6)(36 - 11)}{2 \times 10^{-3}}

\frac{dQ}{dt} = 800 J/s

8 0
3 years ago
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