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weeeeeb [17]
3 years ago
9

Why is carbon tetrachloride a liquid at room temperature

Chemistry
1 answer:
miv72 [106K]3 years ago
3 0
Because I'm the warm it melts in the cold it's frozen
You might be interested in
Nitrogen and hydrogen combine to form ammonia.
zhenek [66]

The balanced chemical equation for the formation ammonia is

    N2(g) + 3H2(g)  ----> 2NH3(g)  .        

The balanced chemical equations explains that the same number of each element exist as reactants and products.  The coefficients in a balanced equation must be the simplest whole number ratio. Mass is always conserved in chemical reactions.

For the formation of ammonia, the chemical equation is

     N2(g) + H2(g)  ----> NH3(g)

Balancing the chemical reaction, we can write,

  N2(g) + 3H2(g)  ----> 2NH3(g)  .  

This equation shows two nitrogen entering the reaction together and two hydrogens entering the reaction together. Since NH3 is multiplied by a coefficient of 2 there are now 2 nitrogen and 6 hydrogens. The 6 hydrogens come from the 2 multiplied by the subscript of 3. This is the balanced chemical reaction.

To learn more about Balanced chemical equation please visit:

brainly.com/question/14072552

#SPJ4

6 0
1 year ago
A titration required 42.00 mL of 0.150 M NaOH. How many moles of NaOH is this?
NARA [144]

Answer:

0.006342moles

Explanation:

1000ml of NaOH contain 0.151moles

42ml of NaOH contain (42*0.151)/1000 moles

=0.006342moles

8 0
2 years ago
How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?
elixir [45]
To calculate the moles of AgNO3 in a solution, we need to know the volume and concentration of the solution. 
Moles of AgNO3 = Volume of AgNO3 solution (L) * concentration of AgNO3 solution (M or mole/L) = 1.50 L * 0.050 M = 0.075 mole.

So 0.075 moles of AgNO3 are present in 1.50 L of a 0.050 M solution.
8 0
3 years ago
Read 2 more answers
The pOH of an aqueous solution at 25°C was found to be 1.20. The pH of this solution is . The hydronium ion concentration is M.
frosja888 [35]

Answer:

pH = 12.80

[H3O+] = 1.58 * 10^-13 M

[OH-] = 0.063 M

Explanation:

Step 1: Data given

pOH = 1.20

Temperature = 25.0 °C

Step 2: Calulate pH

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 1.20 = 12.80

Step 3: Calculate hydronium ion concentration

pH = -log[H+] = -log[H3O+]

12.80 = -log[H3O+]

10^-12.80 = [H3O+] = 1.58 * 10^-13 M

Step 4: Calculate the hydroxide ion concentration

pOH = 1.20 = -log [OH-]

10^-1.20 = [OH-] = 0.063M

Step 5: Control [H3O+] and [OH-]

[H3O+]*[OH-] = 1* 10^-14

1.58 *10^-13 * 0.063 = 1* 10^-14

5 0
3 years ago
How can I balance chemical equations by providing the correct coefficients? For example: [?]Pb(NO3)2 + [?]NaCrO4 = [?]PbCrO4 + [
melomori [17]

Answer:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃

The coefficients are: 1, 1, 1, 2

Explanation:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃

The above equation can be balance as follow:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + NaNO₃

There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 2 before NaNO₃ as shown below:

Pb(NO₃)₂ + Na₂CrO₄ —> PbCrO₄ + 2NaNO₃

Now the equation is balanced.

The coefficients are: 1, 1, 1, 2

3 0
2 years ago
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