0.1 mol/L
. The concentration of the HCl is 0.1 mol/L
a) Write the <em>balanced chemical equation
</em>
HCl + NaOH → NaCl + H2O
b) Calculate the <em>moles of NaOH
</em>
Moles of NaOH = 0.050 L NaOH x (0.1 mol NaOH/1 L NaOH)
= 0.0050 mol NaOH
c) Calculate the <em>moles of HCl
</em>
Moles of HCl = 0.0050 mol NaOH x (1 mol HCl/1 mol NaOH)
= 0.0050 mol HCl
d) Calculate the <em>molar concentration</em> of the HCl
<em>c</em> = moles/litres = 0.0050 mol/0.050 L = 0.1 mol/L
Equation for the standard formation of solid sodium orthosilicate:
4 Na(s) + Si(s) + 2 O₂(g) → Na₄SiO₄(s)
Answer:
Carbon = 1s2 2s2 2p2 group= 14 period = 2
Explanation:
group can be taken from the electronic configuration here it is 2s2 2p2 so it should belongs to 4A or 14
The mass of carbon in 1 liter of mixture = 1.108 g
<h3>What is the mass of carbon in 1 liter of the mixture?</h3>
The mass of carbon in 1 liter of the mixture is determined as follows:
First the moles of gas is determined using the ideal gas formula:
n = (1 * 1)/(0.08205L * 298)
n = 0.0409 mole of total gas
mass of gas is then determined using the formula:
mass = 1 * 1.375
mass = 1.375 g
Let x = mass of CH₄ and y = mass of C₄H₁₀
x + y = 1.375 g
nCH₄ + nC₄H₁₀ = ntotat
moles = mass/molar mass
x + y = 1.695 => y = 1.695 - x
(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409
x/16 + (1.375 - x)/58 = 0.0409
x = 0.380 g CH₄
y = 1.375 - 0.380
y = 0.995 g of C₄H₁₀
mass of C in CH₄ = 12/16 * 0.380 = 0.285
mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823
Mass of carbon in 1 liter of mixture = 0.285 + 0.823
Mass of carbon in 1 liter of mixture = 1.108 g
In conclusion, the carbon is the major component in the mixture.
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