The ΔG° for the reaction in kJ/mol is -17.09.
Calculation,
The reaction is given below.
→
The ΔG° for = -5.5 kJ/mol
The ΔG° for = -22.59 kJ/mol
The ΔG° for = 0 kJ/mol ( change in gibb's free energy of standard state )
ΔG° for the reaction = ΔG° (product) - ΔG° (reactant)
ΔG° for the reaction = -22.59 kJ/mol - ( -5.5 kJ/mol + 0 kJ/mol )
ΔG° for the reaction = -17.09 kJ/mol
The value of change standard gibb's free energy for the standard state ( most stable form of elements) is zero.
learn about gibb's free energy
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A. K+, OH-
B. C6H5CO+, OH-
C. NH4+, Cl-
D. Mg++, 2 NO3-
Everything has 1 except for the Nitrate ion in D, which has 2
Heptane has nine structural isomers are 2-methylhexane, 3-methylhexane, 2,2-dimethylpentane, 2,3-dimethylpentane, 2,4-dimethylpentane, 3,3-dimethylpentane, 3-ethylpentane and 2,2,3-trimethylbutane. Each compound must have the same molecular formula but the structure of each are different from each other.
6.941u? Sorry if I get it wrong
<span>decomposition of SrCO3 to SrO and CO2 =change in mass
moles of CO2 =(1.850 g - 1.445 g).
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
</span><span> mass ratio = 1.358/1.850 = 0.7341, </span>
or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps