The answer for this one is a
According to the law of conservation of mass, the amount of BARIUM present of the reactants is the same as the amount present in the products (the precipitate).
(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt
(10.0 g) / (0.0480 mol) = 208.3 g/mol
So it must have been BaCl2, because the molar mass of Barium is 137 which leave 71 grams left. Since Barium is a +2 charge, it means the atom next to it must be twice. Chlorine mass is 35, which twice is 71
Answer:
boron (B), germanium (Ge), and tellurium (Te)
Answer:
Explanation:
First digit of the 2p^3 gives you value of n, in this case its = 2, So, n= 2
Second alphabet gives you the value of l,
l=0 =s
l=1 =p
l=3=d
l=4=f
since "p" is the alphabet in 2p^3, so in your case lt shoudlbe = 1 right?
ml= -l to +l , that is -1, 0, +1
Ms= +1/2 or -1/2 alaways remains same foe evrything.
