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3 years ago

10

Watts are a measurement of power

2 answers:

coldgirl [10]3 years ago

6 0

Answer:

Watts are a measurement of power, describing the rate at which electricity is being used at a specific moment. For example, a 15-watt LED light bulb draws 15 watts of electricity at any moment when turned on. Watt-hours are a measurement of energy, describing the total amount of electricity used over time.

<u><em>Please mark as brainliest.</em></u>

Harrizon [31]3 years ago

3 0

Answer: True

Watts are a measurement of power, used in light bulbs and other electricity. It is also measured as candela (C) in SI Units. The answer to the question is true because of this measurement.

Hope this helps!

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Extension: Cedric has been in the hospital for 15 weeks, how many minutes is that? Use

almond37 [142]

Answer:

151200 minutes.

Explanation:

From the question given above, the following data were obtained:

Time (in week) = 15 weeks

Time (in min) =?

Next, we shall convert 15 weeks to days. This can be obtained as follow:

1 week = 7 days

Therefore,

15 weeks = 15 weeks × 7 days / 1 week

15 weeks = 105 days

Next, we shall convert 105 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

105 days = 105 days × 24 h / 1 day

105 days = 2520 h

Finally, we shall convert 2520 h to mins. This can be obtained as follow:

1 h = 60 mins

Therefore,

2520 h = 2520 h × 60 mins / 1 h

2520 h = 151200 mins

Thus, 15 weeks is equivalent to 151200 minutes.

6 0

3 years ago

Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to

denis-greek [22]

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒ Mass of solution = $Mass \ of \ (NaCl+H_2O)$

= $51.56+164.2$

= $215.76 \ g$

hence,

⇒ $Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100$

$=\frac{51.56}{215.76}\times 100$

$=23.896 \ percent$

4 0

3 years ago

A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e

german

Answer: 8.57 ml of KOH is required to reach the equivalence point.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HNO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?$

Putting values in above equation, we get:

$1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL$

Thus 8.57 ml of KOH is required to reach the equivalence point.

8 0

4 years ago

(IM ONLY ALOWED TO GIVE 10 POINTS) Sound travels at a speed of 330 m/s. How long does it take for the sound of thunder to travel

dlinn [17]

5.28 seconds. Hope this helps

6 0

3 years ago

When a scientific theory has been tested and proved by the scientific community, it

beks73 [17]

Answer:

True

Explanation:

When a theory is proven over and over it will become a law

3 0

3 years ago

Read 2 more answers