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dezoksy [38]
3 years ago
10

Watts are a measurement of power

Chemistry
2 answers:
coldgirl [10]3 years ago
6 0

Answer:

Watts are a measurement of power, describing the rate at which electricity is being used at a specific moment. For example, a 15-watt LED light bulb draws 15 watts of electricity at any moment when turned on. Watt-hours are a measurement of energy, describing the total amount of electricity used over time.

<u><em>Please mark as brainliest.</em></u>

Harrizon [31]3 years ago
3 0

Answer: True

Watts are a measurement of power, used in light bulbs and other electricity. It is also measured as candela (C) in SI Units. The answer to the question is true because of this measurement.

Hope this helps!

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239<br> 239<br> -<br> 93Np<br> 94Pu + c
seraphim [82]

Answer:4>34.1>56

Explanation:ez

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2 years ago
Please help!!!!!!!!!!!!!!!
svlad2 [7]
The 2nd one is the right answer

Hope this helped
3 0
3 years ago
What pressure will be produced when 2.0 moles of N2 gas is heated to 68oC in a container that holds 1.25 of gas?
Stella [2.4K]

The pressure of the nitrogen gas produced is determined as 44.77 atm.

<h3>What is the pressure of the Nitrogen gas?</h3>

The pressure of the nitrogen gas is determined from ideal gas equation, as shown below;

PV = nRT

P = nRT/V

where;

  • n is number of moles = 2 moles
  • R is ideal gas constant = 0.08205 L.atm/mol.K
  • T is temperature = 68⁰C = 68 + 273 = 341 K
  • V is volume = 1.25 L

P = (2 x 0.08205 x 341)/(1.25)

P = 44.77 atm.

Learn more about pressure here: brainly.com/question/25736513

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3 0
2 years ago
If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol
igomit [66]

Answer:

\Delta _RH=4x10^{-3}\frac{kJ}{mol}

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}

Best regards.

5 0
2 years ago
A student dissolves equal amounts of salt in equal amounts of warm water, room-temperature water, and ice water. Which result is
Tanya [424]

doesnt salt desolve ice? so wouldn't the salt dissolve in the ice water?

6 0
3 years ago
Read 2 more answers
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