Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1, the ball bounces
1 answer:
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Let's call h the initial height of the rock (h=50 m, the height of the bridge).
Initially, the rock has only gravitational potential energy, which is given by
where m=10 kg is the mass of the rock while g is the gravitational acceleration. So, the total mechanical energy of the rock at this point is
At midway point of its fall, its height is
, so its potential energy is
But now the rock is also moving by speed v, so it also has kinetic energy:
So the total energy at the midway point of the fall is
(1)
The mechanical energy must be conserved, so
, so we can rewrite (1) and solve it to find the kinetic energy of the rock at midway point of its fall:
Initially, the rock has only gravitational potential energy, which is given by
where m=10 kg is the mass of the rock while g is the gravitational acceleration. So, the total mechanical energy of the rock at this point is
At midway point of its fall, its height is
But now the rock is also moving by speed v, so it also has kinetic energy:
So the total energy at the midway point of the fall is
The mechanical energy must be conserved, so
Answer:
Force between two charges is given as 1.296 N
Explanation:
As we know that the two charges will attract or repel each other when they are placed near to each other
Here we know that electrostatic force is given as
here we have
distance between two charges is given as
r = 0.50 m
so we have