Drag, D = 1/2*Drag coefficient*density of air*velocity^2*Frontal area
Where,
Density of air ≈ 1.225 kg/m^3
Velocity = 55 mph = 24.5872 m/s
Drag coefficient = 0.21
Frontal area = 30 ft^2 = 2.78709 m^2
Substituting;
D = 0.5*0.21*1.225*24.5872^2*2.78709 = 216.72 N
The bowling ball rolling down the bowling lane because even if you have one in the driveway on a hot day it still isn't moving. Hope this helps XD
Answer:
15.9 m
Explanation:
Use the equation for gravitational potential energy (Ug):
Ug= mass*g*height
250,000 J= 1600 kg*9.8 m/s^2*height
height= 15.9 m
Hope this helps!!! :)
