These cases are rare, but what happens is something called an occluded front. There are so many things that could be talked about and results aren't typically constant, so I recommend you look up what an occluded front is. Its basically when a cold front catches up to a warm front and forces even more warm air up, causing high amounts of precipitation.
The pilot might be correct (I think), because, if the gravity of the planet is strong, then the planet’s gravity will pull the spaceship into its orbit, so the engines don’t need to be on for the ship to get pushed toward the planet.
Answer:
The distance traveled by the balloon is 10.77 m
Explanation:
velocity of the ball,
= 2 m/s south
velocity of the air,
= 5 m/s west
To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.
| 2m/s
|
|
↓
5m/s ←------------------
the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.
R² = 5² + 2²
R² = 29
R = √29
R = 5.385 m/s
The distance traveled by the balloon is calculated as;
d = R x t
where;
t is time of the motion = 2 seconds
d = 5.385 x 2
d = 10.77 m
Therefore, the distance traveled by the balloon is 10.77 m.
#3, they both come after infared and are not harmful to living cells.
The answer you have is right good job 12