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3 years ago

What do you mean by magnitude of an electric field due to a point charge. State its SI unit.

1 answer:

3 0

Electric field strength is the force acting on a 1 Coulomb of positive change at that point. It is measured in Newton per Coulomb.

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Why does ice melt faster in water than in oil when both liquids are at the same temperature

vekshin1

Water has a high specific heat capacity. Oil has a smaller heat capacity.

7 0

3 years ago

Read 2 more answers

The energy in the typical thunderstorm is about 1.4×1011j. a typical lightning flash transfers 30 c across a potential differenc

iragen [17]

780 seconds, or 13 minutes.

In the future, please use proper capitalization. There's a significant difference in the meaning between mV and MV. One of them indicated millivolts while the other indicates megavolts. For this problem, I'll make the following assumptions about the values presented. They are:
Total energy = 1.4x10^11 Joules (J)
Current per flash = 30 Columbs (C)
Potential difference = 30 Mega Volts (MV)

First, let's determine the power discharged by each bolt. That would be the current multiplied by the voltage, so
30 C * 30x10^6 V = 9x10^8 CV = 9x10^8 J

Now that we know how many joules are dissipated per flash, let's determine how flashes are needed.
1.4x10^11 / 9x10^8 = 1.56E+02 = 156

Since each flash takes 5 seconds, that means that it will take about 5 * 156 = 780 seconds which is about 780/60 = 13 minutes.

3 0

3 years ago

The earth has a radius of 6.38 × 106 m and turns on its axis once every 23.9 h.

Vladimir [108]

Answer:

a) V = 465.9 m/s

b) θ = 70.529°

Explanation:

Let's first calculate angular velocity of earth:

$\omega=\frac{2\pi}{23.9h}*1h/3600s$

Velocity of a person on Ecuador will be:

$V_E = \omega*R$

$V_E = 465.9 m/s$

For part b, since angular velocity is the same:

$\frac{\omega*R}{3}=\omega*(R*cos\theta )$

Solving for θ:

$\theta=acos(1/3)$

$\theta=70.529\°$

8 0

3 years ago

Two blocks, m1=70.0kg and m2=120.0kg, are connected as shown. The coefficient of friction between surfaces in contact is 0.250.

andriy [413]

If they are connected exactly as shown, nothing can happen.

3 0

3 years ago

A proton moving in the positive x direction with a speed of 9.9 105 m/s experiences zero magnetic force. When it moves in the po

Alex

Answer:

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

Explanation:

In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:

$\vec{F_B}=q\vec{v}\ X\ \vec{B}$ (1)

v: speed of the proton = 9.9*10^5 m/s

q: charge of the proton = 1.6*10^-19C

B: magnetic field = ?

FB: magnetic force on the proton = 1.6*10^-13N

When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:

^j X (-^i) = -(-^k)=^k

To obtain the magnitude of the magnetic field you use:

$F_B=qvBsin90\°=qvB\\\\B=\frac{F_B}{qv}=\frac{1.6*10^{-13}N}{(1.6*10^{-19}C)(9.9*10^5m/s)}\\\\B=1.01T$

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

8 0

3 years ago