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3 years ago

What is the definition of density

Physics

2 answers:

madam [21]3 years ago

8 0

Answer:

the degree of compactness of a substance.

Explanation:

The density, of a substance is its mass per unit volume. The symbol most often used for density is ρ, although the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume: where ρ is the density, m is the mass, and V is the volume. Wikipedia

MakcuM [25]3 years ago

5 0

Answer:

The quantity of mass per unit volume of a substance

Explanation:

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4 years ago

A rocket accelerates upward from rest, due to the first stage, with a constant acceleration of a1 = 67 m/s2 for t1 = 39 s. The f

Igoryamba

Answer:

(a) $v_1= a_1t_1$

(b) $v_2 =a_1t_1+a_2t_2$

(c) 44133.5 m

Explanation:

Given:

$u$ = initial speed of the rocket in the first stage = 0 m/s
$v_1$ = final speed of the rocket in the first stage
$v_2$ = final speed of the rocket in the second stage
$t_1$ = time interval of the first stage
$t_2$ = time interval of the second stage
$s_1$ = distance traveled by the rocket in the first stage

$s_2$ = distance traveled by the rocket in the second stage
$s$ = distance traveled by the rocket in whole time interval

Part (a):

Since the rocket travels at constant acceleration.

$\therefore v_1 = u+a_1t_1\\\Rightarrow v_1 = a_1t_1$

Hence, the expression of the rocket's speed at time $t_1\ is\ v_1 = a_1t_1$ .

Part (b):

In this part also, the rocket moves with a constant acceleration motion.

$\therefore v_2 = v_1+a_2t_2\\\Rightarrow v_2 = a_1t_1+a_2t_2$

Hence, the expression of the rocket's speed in the time interval $t_2$ is $v_2 = a_1t_1+a_2t_2$ .

Part (c):

For the constant acceleration of rocket, let us first calculate the distance traveled by the rocket in both the time intervals.

$s_1 = u+\dfrac{1}{2}a_1t_1^2\\\Rightarrow s_1 = 0+\dfrac{1}{2}67\times(1)^2\\\Rightarrow s_1 =33.5\ m$

Similarly,

$s_2 = v_1t_2+\dfrac{1}{2}a_2t_2^2\\\Rightarrow s_2 = a_1t_1t_2+\dfrac{1}{2}a_2t_2^2\\\Rightarrow s_2 = 67\times1\times49+\dfrac{1}{2}\times 34\times(49)^2\\\Rightarrow s_2 =44100\ m\\\therefore s = s_1+s_2\\\Rightarrow s = 33.5\ m+44100\ m\\\Rightarrow s =44133.5\ m$

Hence, the rocket moves a total distance of 44133.5 m until the end of the second period of acceleration.

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3 years ago

Read 2 more answers

A man standing on top of a 30 m tall building throws a brick downwards with a velocity of 12 m/s. Determine the speed of the bri

BlackZzzverrR [31]

Answer:

27.1m/s

Explanation:

Given parameters:

Height of the building = 30m

Initial velocity = 12m/s

Unknown:

Final velocity = ?

Solution:

We apply one of the kinematics equation to solve this problem:

v² = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

v² = 12² + (2 x 9.8 x 30)

v = 27.1m/s

7 0

3 years ago