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krok68 [10]
3 years ago
14

Calculate the number of moles contained in 550ml of carbon dionide at stp

Chemistry
1 answer:
g100num [7]3 years ago
3 0
The answer is 20 I think
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Low tide____.
Fantom [35]

Answer:

i think the answer is A

Explanation:

because in some areas, a regular pattern occurs of one high tide and one low tide each day,

8 0
3 years ago
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would you expect the N-O bond in HNO2 to be longer, shorter, or the same length as the N-O bonds in NO2^-
prohojiy [21]
Longer, this is because the H in HNO2 is bonded with an oxygen, no longer allowing this structure to have a resonance structure.
NO2 on the other hand has one double bond and one single bond, so it has a resonance structure. And resonance structures are actually one structure so there isn't really a single and double bond, it's actually a 1 and 1/2 bond that calls for a higher bond order.
And I higher bond order will result in a shorter lengths!
I hope this helps out!!! And just out of curiosity, is this off of an AP FRQ packet??
8 0
3 years ago
A hypothetical element has three main isotopes with mass numbers of 51, 53, and 54. If 15.00% of the isotopes have a mass number
Eva8 [605]

Answer: 53.25

Explanation: Please see attachment for explanation. Thanks.!

5 0
3 years ago
Which clouds are often associated with thunder and lightning?
FrozenT [24]
Cumulonimbus clouds, of course!. These clouds are known to carry rain, hail, and thunder. Bigger versions are known as supercells, deadly storms that can spew out tons of rain, hail, wind, and even tornadoes!
6 0
3 years ago
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Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
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