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3 years ago

Npk fertilizer is called a complete fertilizer,why?

Physics

1 answer:

blsea [12.9K]3 years ago

4 0

Answer:

Complete fertilizers or balanced fertilizers are so-called because of their amounts of nitrogen, phosphorus, and potassium. ... If your soil already had an excess of one of the three nutrients in NPK, you could actually be harming some of your plants by adding more of it to the soil

Explanation:

You might be interested in

a bird flies at a speed of 15 m/s for 10s, 20 m/s for 20s, and 30 m/s for 15s. what is the birds average speed

gtnhenbr [62]

Average speed = (total distance) / (total time)

First segment:

15 m/s for 10 sec; distance covered = (15 x 10) = 150 m

Second segment:

20 m/s for 20 sec; distance covered = (20 x 20) = 400 m

Third segment:

30 m/s for 15 sec; distrance covered = (30 x 15) = 450 m

Total time = (10s + 20s + 15s) = 45 sec

Total distance = (150m + 400m + 450m) = 1,000 m (1 km)

<em>Average speed</em> = (1,000 m) / (45 sec) = <em>22.22 m/s</em>

7 0

4 years ago

A 97.3 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.67 r

Yuliya22 [10]

Answer:

w = 1.14 rad / s

Explanation:

This is an angular momentum exercise. Let's define a system formed by the three bodies, the platform, the bananas and the monkey, in such a way that the torques during the collision have been internal and the angular momentum is preserved.

Initial instant. The platform alone

L₀ = I w₀

Final moment. When the bananas are on the shelf

we approximate the bananas as a point load and the distance is indicated

x = 0.45m

L_f = (m x² + I ) w₁

angular momentum is conserved

L₀ = L_f

I w₀ = (m x² + I) w₁

w₁ = $\frac{I}{m x^2 + I} \ w_o$

Let's repeat for the platform with the bananas and the monkey is the one that falls for x₂ = 1.73 m

initial instant. The platform and bananas alone

L₀ = I₁ w₁

I₁ = (m x² + I)

final instant. After the crash

L_f = I w

L_f = (I₁ + M x₂²) w

the moment is preserved

L₀ = L_f

(m x² + I) w₁ = ((m x² + I) + M x₂²) w

(m x² + I) w₁ = (I + m x² + M x₂²) w

we substitute

w = $\frac{m x^2 +I}{I + m x^2 + M x_2^2} \ \frac{I}{m x^2 + I} \ w_o$

w = $\frac{I}{I + m x^2 + M x_2^2} \ w_o$

the moment of inertia of a circular disk is

I = ½ m_p x₂²

we substitute

w = $\frac{ \frac{1}{2} m_p x_2^2 }{ \frac{1}{2} m_p x_2^2 + M x_2^2 + m x^2} \ \ w_o$

let's calculate

w = $\frac{ \frac{1}{2} \ 97.3 \ 1.73^2 }{ \frac{1}{2} \ 97.3 \ 1.73^2 + 21.9 \ 1.73^2 + 9.67 \ 0.45^2 } \ \ 1.67$

w = $\frac{145.60 }{145.60 \ + 65.54 \ + 1.958} \ \ 1.67$

w = 1.14 rad / s

5 0

3 years ago

I'm solving for the angle on a right triangle the hypotenuse is 36 and the base is 24 I don't understand how or when to use cos

Alika [10]

Given

hypotenuse is 36

base is 24

Procedure

Cos function (or cosine function) in a triangle is the ratio of the adjacent side to that of the hypotenuse. The cosine function is one of the three main primary trigonometric functions and it is itself the complement of sine(co+sine).

$\begin{gathered} \cos \theta=\frac{24}{36} \\ \theta=\cos ^{-1}(\frac{24}{36}) \\ \theta=48.1 \end{gathered}$

The answer would be 48 degrees

4 0

1 year ago

A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a verti

Angelina_Jolie [31]

Hi there!

Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:

Wsinθ = downward acceleration along incline due to gravity (N)

Fκ = kinetic friction force along incline (N)

A = applied force (N)

The acceleration due to gravity and friction force act in the same direction, so:

Wsinθ + Fκ = A

Solve for sinθ using right triangle trigonometry:

sinθ = O/H = 3/6 = 0.5

Rearrange the equation for the force of kinetic friction and solve:

Fκ = A - 0.5W

Fκ = 30.4 - 20 = 10.4 N

Now, recall that:

Work = Force × displacement (W = F × d)

Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:

W = Fdcosθ

Angle between displacement and friction force is 180°.

cos(180) = -1

Work done by friction = -Fd = -10.4(6) = -62.4 J

8 0

3 years ago

A 1.0-kg block moving to the right at speed 3.0 m/s collides with an identical block also moving to the right at a speed 1.0 m/s

____ [38]

Answer:

Speed of both blocks after collision is 2 m/s

Explanation:

It is given that,

Mass of both blocks, m₁ = m₂ = 1 kg

Velocity of first block, u₁ = 3 m/s

Velocity of other block, u₂ = 1 m/s

Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)v$

$v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$v=\dfrac{1\ kg\times 3\ m/s+1\ kg\times 1\ m/s}{2\ kg}$

v = 2 m/s

Hence, their speed after collision is 2 m/s.

7 0

4 years ago

Npk fertilizer is called a complete fertilizer,why?​

Npk fertilizer is called a complete fertilizer,why?