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Troyanec [42]
3 years ago
8

The formula for table salt is NaCl. According to the law of definite proportions, this means that the formula for table salt ___

_.
A. Can also be NaCl2.
B. Is always NaCl.
C. Must contain Na and Cl in some proportion.
D. Is likely to be NaCl in most cases.
Chemistry
2 answers:
Natalka [10]3 years ago
5 0
The answer is c.
Hoped this helped!
lilavasa [31]3 years ago
5 0
The anwser is B.Is always NaCI
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A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al
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Answer:

0.384\ \text{L}

Explanation:

P_1 = Initial pressure = 931 torr = 931\times \dfrac{101.325}{760}=124.12\ \text{kPa}

P_2 = Final pressure = 113 kPa

V_1 = Initial volume = 350 mL

V_2 = Final volume

From the Boyle's law we have

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}

The volume the gas would occupy is 0.384\ \text{L}.

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2 years ago
Which of the following properties tells the most about the stability of a metal?
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I believe the answer is A
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On a heating curve, in which section(s) would you use the equation, Q=mCΔT, to calculate the total heat required?
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Answer:

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A substance has a mass of 360 g and a volume of 7.5 cm3. What is its density?
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D = g / cm³

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Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h2c2o4 and h2o in th
shusha [124]

Answer:

See explanation below

Explanation:

The overall reaction, is:

MnO4⁻(aq) + H₂C₂O₄(aq) ---------> Mn²⁺(aq) + CO₂(g)

Balancing this redox reaction means that one compound is reducting while the other is oxidizing. So, we need to separate both compounds into 2 semi equations and balance both of them, per separate and then, we can join them.

As we want to balance in acid medium, means that we need to add water and H⁺ in both reactions. Doing that we have the following:

MnO₄⁻   ---------------> Mn²⁺

In this reaction, we can clearly see that it's not balanced. To balance this semi equation, let's see the elements. In the reactans we have Mn and O, but in the products we only have Mn, the atom of oxygen where could it be? As we are doing acid medium, if in the reactants we have oxygen, this oxygen can be as products in the form of water, so we add water there.

MnO₄⁻   ---------------> Mn²⁺ + H₂O

Now, the water has hydrogen atoms, and if we are in acid medium, the hydrogen can only come from the acid medium, and in this case H⁺ so:

H⁺ + MnO₄⁻ ----------> Mn²⁺ + H₂O

Now, it's time to balance the charges. First Mn²⁺ is the lowest oxidation state of the manganese, this means that in the reactants Mn is passing from a higher state to a lower state, therefore, this compouns is reducting. How many electrons? well, in this case, we know that oxygen usually have the oxidation state -2, so the manganese would be:

(-2 * 4) + x = -1

-8 + x = -1 -------> x = +7

Therefore, manganese passes from 7+ to 2+, it's gaining 5 electrons so:

H⁺ + MnO₄⁻ + 5e⁻ ----------> Mn²⁺ + H₂O

Finally, we just balance the masses and charges:

8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O

Now, we just do the same thing with the other semi equation which is oxydizing. The explanation of that, is similar to this, so I'm gonna do it directly:

C₂O₄²⁻ -----------> CO₂

In this case, we can easily see that carbon is losing 2 electrons, so, let's put the 2 electrons on the product to balance the charges, and then, the masses:

C₂O₄²⁻ -----------> CO₂ + 2e⁻

C₂O₄²⁻ -----------> 2CO₂ + 2e⁻

Let's join both equations and do the sum of them:

8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O

C₂O₄²⁻ -----------> 2CO₂ + 2e⁻

As we can see, we do not have the same electrons on both equations, we need to equal those values so:

2 * (8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O)

5 * (C₂O₄²⁻ -----------> 2CO₂ + 2e⁻)

16H⁺ + 2MnO₄⁻ + 10e⁻----------> 2Mn²⁺ + 8H₂O

5C₂O₄²⁻ -----------> 10CO₂ + 10e⁻

Now, let's sum both equations:

16H⁺ + 2MnO₄⁻ + 10e⁻----------> 2Mn²⁺ + 8H₂O

5C₂O₄²⁻ -----------> 10CO₂ + 10e⁻

___________________________________

16H⁺ + 2MnO₄⁻ + 5C₂O₄²⁻ -----------> 2Mn²⁺ + 10CO₂ + 8H₂O

This would be the balanced reaction, however, let's put it as it was originally with the H2 in the C2O4 and balance it:

<h2>2MnO₄⁻ + 5H₂C₂O₄ + 6H⁺ -----------> 2Mn²⁺ + 10CO₂ + 8H₂O</h2>
7 0
3 years ago
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