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masha68 [24]
3 years ago
5

How do you calculate the average density of two different fluids?

Physics
1 answer:
ANTONII [103]3 years ago
4 0
-- Take a sample of the first fluid.
-- Measure its mass.
-- Measure its volume.
-- Divide its mass by its volume.
   This gives you the density of the first fluid.

-- Take a sample of the second fluid.
-- Measure its mass.
-- Measure its volume.
-- Divide its mass by its volume.
   This gives you the density of the second fluid.

You want their average ?
OK

-- Add  (Density of the first fluid) + (Density of the second fluid).
-- Divide the sum by  2 .

   Now you have the average of the two densities.

Note:
That's NOT necessarily the density of a mixture when you
pour some of fluid-1 and fluid-2 into a jar.  The density of the
fluid in the jar is going to depend on how much of each fluid is
in there. 
I started to calculate how much of each one has to be there in order
for the density of the mixture to be equal to the average of their two
densities. But then I sat up straight, asked myself "Why ? !" . 
Then I stopped, and went into the kitchen and ate some meatloaf.
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<u>Answer</u>

D) 3100 Liters


<u>Explanation</u>

To get the volume if the balloon you need to use the combined equation of the low of gases.

P₁V₁/T₁ = P₂V₂/T₂

(20×150)/(27+273) = (1×V₂)/(37+273)

3000/300 = V₂/310

10 = V₂/310

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7 0
3 years ago
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A vertical spring has a mass hanging from it, which is displaced from the equilibrium position and begins to oscillate. At what
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Answer:

the object has least potential energy at mean position of the SHM

Explanation:

If a block is connected with a spring and there is no resistive force on the system

In this case the total energy of the system is always conserved and it will change from one form to another form

So here we will say that

Kinetic energy + Potential energy = Total Mechanical energy

As we can say that total energy is conserved so here we have least potential energy when the system has maximum kinetic energy

So here we also know that at mean position of the SHM the system has maximum speed and hence maximum kinetic energy.

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5 0
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The moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is
sleet_krkn [62]

Answer:

I = I₀ + M(L/2)²

Explanation:

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The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.

The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀

The distance between the two axes is L/2 (total length of the rod divided by 2

From the parallel axis theorem we have

I = I₀ + M(L/2)²

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Answer:

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In the x direction, the velocity is constant at 30 m/s.

The overall speed is:

v² = (30 m/s)² + (40 m/s)²

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The new resistance comes out to be = 4 times of original resistance .

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