The colors of light emitted from heated atoms had very specific energies.
Answer: The earth is a noisy place. Seismometers, which measure ground movements to detect earthquakes, volcanic eruptions, and manmade explosives, are constantly recording smaller vibrations caused by ocean waves, rushing rivers, and industrial activity.
Explanation:
The terminal velocity of gold sphere is 39.2 cm/s
<h3>What is terminal velocity?</h3>
Terminal velocity is the maximum velocity attainable for an object as it falls through a fluid.
<h3>How to calculate the terminal velocity of the gold sphere?</h3>
The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where
- g = acceleration due to gravity = 9.8 m/s²,
- r = radius of sphere = 100 μm = 100 × 10⁻⁶ m = 10⁻⁴ m = 10⁻² cm,
- ρ = density of sphere = 19 g/cm³,
- σ = density of water = 1.0 g/cm³ and
- η = viscosity of water = 10⁻³ Pa-s
So, susbtituting the values of the variables into the equation, we have that
v = 2gr²(ρ - σ)/9η
v = 2 × 9.8m/s²× (10⁻² cm)²(19 g/cm³ - 1.0 g/cm³)/(9 × 10⁻³ Pa-s)
v = 2 × 9.8 m/s² × 10⁻⁴ cm² × (18 g/cm³)/(9 × 10⁻³ Pa-s)
v = 2 × 980 cm/s² × 10⁻⁴ cm² × 2 g/cm³/(1 × 10⁻³ Pa-s)
v = 3920 g/s² × 10⁻⁴/(1 × 10⁻³ Pa-s)
v = 392 cm/s × 10³ × 10⁻⁴
v = 392 × 10⁻¹ cm/s
v = 39.2 cm/s
So, the terminal velocity is 39.2 cm/s
Learn more about terminal velocity of sphere here:
brainly.com/question/21684177
#SPJ1
If it takes
seconds to reach the car, then the distance
is
.
The bear's distance from the tourist's starting point is
For maximum
, we set the equations equal to each other:
so the distance is
Answer:
The velocity of the boat after the batman lands in it is +9.26 m/s
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
Note: The collision between the Batman and the boat is an inelastic collision.
m'u'+mu = V(m+m').................... Equation 1
Where m' = mass of the Batman, u' = initial velcoity of the batman, m = mass of the boat, u = initial velocity of the boat, V = common velocity.
make V the subject of equation 1
V = (m'u'+mu)/(m+m')............... Equation 2
Given: m' = 96.1 kg, u' = 0 m/s, m = 458 kg, u = +11.3 m/s.
Substitute these values into equation 2
V = [(96.1×0)+(458×11.2)]/(96.1+458)
V = 5129.6/554.1
V = +9.26 m/s
