Answer:
1890J
Explanation:
375+45 = 420kg (total mass)
kinetic energy = 1/2 × mass × velocity²
1/2 × 420 × 3² = 1890J
Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is
, and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
Answer: C) divide: distance ÷ velocity
Explanation:
The velocity
equation is distance
divided by time
:

If we isolate
we will have:

Hence, the correct option is C: distance divided by velocity.
Answer:
5.90 ft/s^2
Explanation:
There are mixed units in this question....convert everything to miles or feet
and hr to s
28 mi / hr = 41.066 ft/s
Displacement = vo t + 1/2 at^2
599 = 41.066 (8.9) + 1/2 a (8.9^2)
solve for a = ~ 5.90 ft/s^2