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Lorico [155]
4 years ago
8

One of the most amusing things a person can experience is when a car in neutral appears to go uphill when its brakes are release

d. Can this really happen? Note that the car is an isolated system with no external force acting on it.

Physics
1 answer:
Serhud [2]4 years ago
8 0

Answer:

No, it cannot happen. It's just an illusion.

Explanation:

We can blame the horizon for this. Generally people is used to seeing the horizon as horizontal (this is perpendicular to the force of gravity). That's why our brains take the horizon as a reference point. The horizon will help our brains tell when something goes up or down.

What is really going on in these particular roads, is that the horizon is inclined downwards, letting our brains think that the road is going upwards, when it's actually going downwards. (See attached picture).

According to physics, gravity always goes in the direction of the center of the earth (downwards). It happens like that everywhere on earth. When the horizon is inclined downwards, our brains think it is horizontal when it actually isn't. It gives us then the illusion that there is a misterious force pulling things upwards and that's why it might appear that the car is going uphill, but it's actually going downwards as usual.

Unless there is an external force (besides gravity) acting on the car, it is impossible that the car will move upwards on a road. That's why the answer is that it cannot really happen, it's just an illusion.

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If i hold a glass full of air upside down, and i take it to the bottom of the swimming pool without tipping it, the density (thi
s2008m [1.1K]
The answer to fill in the blank in the question above is "greater than" based on the physic of the air density. The density of air is affected by the temperature and the pressure based on the ideal gas law. A high pressure will make the air becomes denser and the bottom of swimming pool has a higher pressure than the surface<span>.</span>
6 0
3 years ago
You are traveling in a convertible with the top down. The car is moving at a constant velocity 28.9 m/s, due east along flat gro
faltersainse [42]

Answer:

91.914138 m

Explanation:

t = Time taken

u = Initial velocity = 15.6 m/s

v = Final velocity = -15.6 m/s (it will hit the ground at this speed)

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{-15.6-15.6}{-9.81}\\\Rightarrow t=3.18042\ s

Distance=Speed\times Time

d=3.18042\times 28.9\\\Rightarrow d=91.914138\ m

The distance the car will travel is 91.914138 m

6 0
3 years ago
Two charged particles, with charges q1=q and q2=4q, are located at a distance d= 2.00cm apart on the x axis. A third charged par
Murrr4er [49]

Answer:

X₃₁ = 0.58 m  and  X₃₂ = -1.38 m

Explanation:

For this exercise we use Newton's second law where the force is the Coulomb force

        F₁₃ - F₂₃ = 0

        F₁₃ = F₂₃

Since all charges are of the same sign, forces are repulsive

        F₁₃ = k q₁ q₃ / r₁₃²

        F₂₃ = k q₂ q₃ / r₂₃²

Let's find the distances

         r₁₃ = x₃- 0

         r₂₃ = 2 –x₃

We substitute

      k q q / x₃² = k 4q q / (2-x₃)²

      q² (2 - x₃)² = 4 q² x₃²

        4- 4x₃ + x₃² = 4 x₃²

        5x₃² + 4 x₃ - 4 = 0

We solve the quadratic equation

        x₃ = [-4 ±√(16 - 4 5 (-4)) ] / 2  5

        x₃ = [-4 ± 9.80] 10

       X₃₁ = 0.58 m

       X₃₂ = -1.38 m

For this two distance it is given that the two forces are equal

7 0
3 years ago
Can an object have a positive position, but a negative velocity? Explain your reasoning.
photoshop1234 [79]

Answer:

Yes

Explanation:

A position describes the position of an object relative to the x/y-axis (or the four cardinal directions). A velocity is a vector quantity, defining speed with direction.

So if an object is in a positive position, it means they are in the positive x-axis direction (or wherever on the scale the positive values are stated to be) and if it has a negative velocity, it means said object is moving in the opposite direction of the positive x-axis. It is possible for the object to still be in the positive position as it's moving with a negative velocity

4 0
3 years ago
Recall that force is a change in momentum over a change in time, the force due to radiation pressure reflected off of a solar sa
Zarrin [17]

Answer:

magnitude of the pressure on the sail in the vicinity of Earth’s Orbit= \frac{2I}{c}

Explanation:

The momentum of a photon is:

p = E/c

E = the photon energy

c = the speed of light.

take the time derivative (gives the force)

F = dp/dt = (dE/dt)/c

F = 2(dE/dt)/c (is doubled for complete reflection of the light)

Intensity has the units of energy per unit time per unit area

=  I

then,

Force/unit area = 2I/c

magnitude of the pressure on the sail in the vicinity of Earth’s Orbit= \frac{2I}{c}

4 0
3 years ago
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