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3 years ago

Identify the intermolecular forces present in each of these substances. hcl, ch4

1 answer:

8 0

<span>Intermolecular Forces present in HCl:
The Electronegativity difference between Chlorine and Hydrogen is 0.96 showing that the bond is polar covalent in nature. The Hydrogen atom is partially positive and Chlorine is partially positive making the molecule Dipole. Hence, the Intermolecular forces present in HCl are Dipole-Dipole Interactions.

</span>Intermolecular Forces present in CH₄:
The Electronegativity difference between Chlorine and Hydrogen is 0.35 showing that the bond is non-polar covalent in nature. Hence, the Intermolecular forces present in CH₄ are London Dispersion Forces.

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3 years ago

#5.) Explain why the rock cycle is referred to as a "cycle".

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How many moles are there in 990 grams of sugar, C12H22011? (Sig Figs, do not

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Answer:

Number of moles = 2.89 mol

Explanation:

Given data:

Number of moles of sugar = ?

Mass of sugar = 990 g

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of C₁₂H₂₂O₁₁:

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3 years ago

Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.

Marrrta [24]

$2Cr + 3CoCl_2$ → $2CrCl_3 + 3Co$

Explanation:

The products formed are chromic chloride and cobalt.

Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

Type of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

Chromium $(Cr)$

Cobaltous Chloride $(CoCl_2)$

Products formed in the reaction are -

Chromic Chloride $(CrCl_3)$

Cobalt $(Co)$

Hence, the chemical reaction is as follows -

$Cr + CoCl_2$ → $CrCl_3 + Co$

For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

$2Cr + 3CoCl_2$ → $2CrCl_3 + 3Co$

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4 years ago