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azamat
3 years ago
6

Identify the intermolecular forces present in each of these substances. hcl, ch4

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
8 0
<span>Intermolecular Forces present in HCl:
                                                           The Electronegativity difference between Chlorine and Hydrogen is 0.96 showing that the bond is polar covalent in nature. The Hydrogen atom is partially positive and Chlorine is partially positive making the molecule Dipole. Hence, the Intermolecular forces present in HCl are Dipole-Dipole Interactions.

</span>Intermolecular Forces present in CH₄:
                                                                The Electronegativity difference between Chlorine and Hydrogen is 0.35 showing that the bond is non-polar covalent in nature. Hence, the Intermolecular forces present in CH₄ are London Dispersion Forces.
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The gas pressure inside a high vacuum chamber is 0.000000132atm. Calculate the gas pressure in mmHg and torr. Round each of your
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Answer:

The gas pressure in both mmHg and torr is 1.00 x10⁻⁴.

Explanation:

The standard atmosphere (1 atm) equals a pressure  of 760 mmHg, where mmHg represents the pressure exerted by a column of mercury  1 mm high. <u>The mmHg unit is also called the torr</u>, after the Italian scientist Evangelista  Torricelli, who invented the barometer. Thus,

1 torr = 1 mmHg  

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Therefore, we do the following conversion:

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3 years ago
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Explain why some people use the term decimal system as a synonym for the metric system?
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3 0
3 years ago
A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrat
Nana76 [90]

Answer:

<u> </u><u>85.952 ml</u> Zn^2^+  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of CoSO_4 =\frac{Given mass }{molar mass}

                                                       =\frac{1.817}{155}

                                                          =0.01172

Molarity = \frac{no. of moles}{volume of solution}

           =\frac{0.01172}{20}

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Excess of EDTA = concentration of EDTA - concentration of CoSO4

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As M1V1 ( Excess of EDTA ) = M2V2 (Zn^2^+)

           0.008419\times100ml=0.009795\times V2

           V2=\frac{0.008419\times100}{0.009795}

             V2 =85.952 ml

Therefore , <u>85.952 ml </u>Zn^2^+ needed to titrate the excess complexing reagent .

3 0
3 years ago
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