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Mazyrski [523]
4 years ago
8

How to work out these problems

Physics
1 answer:
Gala2k [10]4 years ago
5 0
For part 2 number 1:
first multiply 3.0 by 20 to get 60. Then multiply 3.0 y 10 to get 30. Add both answers together to get 90. The answer is 90 meters per second squared.
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There is a large box and a small box on a table. The same force is applied to both boxes. The large box moves two feet and the s
stepladder [879]
It would depend on the directions of the boxes, but I believe there would be 3 units of work.
8 0
3 years ago
Read 2 more answers
App182.studyisland.com/cfw/test/practice-session/a56do?CFID=14068
Alex

The amount of matter contained by an object is called mass.

A. mass

<u>Explanation:</u>

Mass is fundamentally a property of any physical amount and it is additionally the estimation of the resistance from the acceleration when force is applied on an object. The mass equals the quality of the gravitational force on a body.

Mass, in material science, the quantitative proportion of idleness, a crucial property of all matter. The greater the mass of a body, the littler the change created by an applied power. The mass of an object can be portrayed by its capacity to oppose a given power (we once in a while call this a body's inertial mass and subsequently mass is personally connected with the idea of inertia).

This is a straightforward result of Newton's second law where the power F, on a body is equivalent to the mass m, times the speeding up an, it encounters, ie:

F=ma or m=F/a

Mass of an object can not be zero but weight can be zero. The mass and weight of an object are different things.

8 0
3 years ago
An energy source forces a constant current of 2A to flow through a light bulbfilament for twenty seconds. If 4.6 kJ is given off
QveST [7]

Answer:

The voltage drop across the bulb is 115 V

Explanation:

The voltage drop equation is given by:

V=\frac{\Delta W}{\Delta q}

Where:

ΔW is the total work done (4.6kJ)

Δq is the total charge

We need to use the definition of electric current to find Δq

I=\frac{\Delta q}{\Delta t}

Where:

I is the current (2 A)

Δt is the time (20 s)

2=\frac{\Delta q}{20}

q=40 C

Then, we can put this value of charge in the voltage equation.

V=\frac{4600}{40}=115 V

Therefore, the voltage drop across the bulb is 115 V.

I hope it helps you!

6 0
3 years ago
How does the graph of velocity vs. time look for something with a constant positive acceleration?
Pie

Answer:

The correct answer is option b.

Explanation:

In velocity vs time graph, vertical axis represent velocity vector and horizontal axis represents time. The slope of the line obtained in this graph is equal to the acceleration.

Slope= \frac{Velocity}{Time}=Acceleration

  • If the line is straight makes an acute angle with horizontal axis then it is considered as positive acceleration.
  • If the line is straight makes an obtuse angle with horizontal axis then it is considered as negative acceleration or deceleration.

8 0
3 years ago
A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
Allisa [31]

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

P₁V₁ / T₁ = P₂ V₂ /T₂

This law is followed by all the gases whether mono atomic or diatomic.

In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

T₂ = ?

From the gas law formula given , we have

T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}

V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.

7 0
3 years ago
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