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love history [14]
2 years ago
5

By experiment, determine what makes a force attractive or repulsive. Describe your experiments and observations with some exampl

es. 4. What evidence do you see that Newton's third law applies to electrostatic forces
Physics
1 answer:
kumpel [21]2 years ago
7 0

Answer:

he combs are brought closer, each one has to move, therefore a force must be applied to each one, and the only force is electrostatic. force must have the same magnitude in each one and in the opposite direction; this description is equivalent to Newton's third law.

Explanation:

A very simple experiment that we can do is to rub a brush or plastic comb with a piece of paper, this creates some electrical charges in the comb, we hang the comb by a thread.

We take another comb and we form it with the same paper, when we bring the combs closer, we see that they repel each other, this is proof that the electrical charges created are of the same type.  

If now we rub the comb with another material, for example plastic, and bring it closer to the comb that is hanging, we see that they are approaching, therefore, it is proven that the load created from another type

With these two simple experiments it can be proved that electric charges are of two types, which are called positive and negative.  

4. In the previous experiment we see that when the combs are brought closer, each one has to move, therefore a force must be applied to each one, and the only force is electrostatic. If we observe carefully we see that the breaking of the combs is the same, therefore the force must have the same magnitude in each one and in the opposite direction; this description is equivalent to Newton's third law.

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In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 4.8 m/s at an
tensa zangetsu [6.8K]
The equation to be used here is the trajectory of a projectile as written below:

y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity

Since the angle is below horizontal, let's use the minus equation. Substituting the values:

- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m

However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.
5 0
3 years ago
Dan is gliding on his skateboard at 2.00 m/s . He suddenly jumps backward off the skateboard, kicking the skateboard forward at
miss Akunina [59]

Answer:

The velocity of Dan is 1.13 m/s.

Explanation:

Given that,

Initial velocity of skateboard and Dan = 2.00 m/s

Velocity of skateboard = 7.00 m/s

Mass of Dan m= 40.0 kg

Mass of skateboard M= 7.00 Kg

Suppose How fast is Dan going as his feet hit the ground?

We need to calculate the initial velocity of Dan

Using conservation of momentum

(m+M)v_{i}=mv_{f}+Mv_{f}

Put the value into the formula

(40.0+7.00)\times2.00=40.0\times v_{i}+7.00\times7.00

v_{i}=\dfrac{(40.0+7.00)\times2.00-7.00\times7.00}{40.0}

v_{i}=1.13\ m/s

Hence, The velocity of Dan is 1.13 m/s.

4 0
3 years ago
A 0.70-kg basketball dropped on a hardwood floor rises back up to 65% of its original height. (a) If the basketball is dropped f
dem82 [27]

Answer:

Part a)

Loss = 3.6 J

Part b)

Loss = 0.99 J

Part C)

This is loss in terms of thermal energy due to collision with the floor

Explanation:

Part a)

Since we know that the ball rises up by 65% of initial height

so after first bounce it will lose 35% of its initial energy

so we will have

U = mgH

Energy Loss = 0.35 mgH[/tex]

Loss = 0.35(0.70)(9.81)(1.5)

Loss = 3.6 J

Part b)

Energy of the ball after first bounce

U_1 = 0.65 mgH

energy of ball after 2nd Bounce

U_2 = 0.65(0.65 mgH)

energy of the ball after 3rd bounce

U_3 = (0.65)(0.65^2)mgH

U_3 = 0.65^3(0.70)(9.81)(1.5)

U_3 = 2.83 J

Now we will have energy loss in fourth bounce given as

Loss = 0.35 U_3

Loss = 0.35(2.83)

Loss = 0.99 J

Part C)

This is loss in terms of thermal energy due to collision with the floor

7 0
3 years ago
What does a wedge do
maxonik [38]
It can be used to separate two objects or portions of an object, lift up an object, or hold an object in place.
4 0
3 years ago
Read 2 more answers
The acceleration due to gravity at the north pole of Neptune is approximately 10.7m/s2. Neptune has mass 1026kg and radius 25000
Scilla [17]

Answer:

(A) Force on the object will be 58.85 N

(B) Apparent weight will be equal to 57.21 N

Explanation:

We have given mass of Neptune m = 1026 kg

Radius R = 25000 Km

Time period = 16 hour

We know that 1 hour = 3600 sec

So 16 hour = 16×86400 = 57600 sec

Acceleration due to gravity at north pole of Neptune g=10.7m/sec^2

(A) Mass of the object m = 5.5 kg

So gravitational force on the object F_g=mg=5.5\times 10.7=58.85N

(B) Velocity will be equal to v=\frac{2\pi R}{T}=\frac{2\times 3.14\times25000\times 1000}{57600}=2725.694m/sec

Apparent weight of the object will be equal to w=f_g-\frac{mv^2}{r}

W=58.85-\frac{5.5\times (2725.694)^2}{25000\times 1000}=57.21N

7 0
3 years ago
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