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3 years ago

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This table shows the acceleration due to gravity on four planets. Planet Gravity (m/s2) Earth 9.8 Mercury 3.7 Neptune 11.2 Uranu

s 8.9 A person would have a different weight on each planet. Arrange the planets in increasing order based on a person’s weight on the planet. Mercury Neptune Earth Uranus < <

2 answers:

son4ous [18]3 years ago

6 0

Answer:

$\Large \boxed{\mathrm{Mercury, \ Uranus, \ Earth, \ Neptune}}$

Explanation:

Earth ⇒ 9.8 m/s²

Mercury ⇒ 3.7 m/s²

Neptune ⇒ 11.2 m/s²

Uranus ⇒ 8.9 m/s²

$W=m \times g$

$\sf {Weight=mass \times acceleration \ due \ to \ gravity}$

The weight of a person can differ on different planets, but the mass stays the same. The greater the acceleration due to gravity, the greater the weight.

Arranging the planets in increasing order based on a person’s weight on the planet:

Mercury, Uranus, Earth, Neptune

arsen [322]3 years ago

3 0

Answer:

Mercury, Uranus, Earth, Neptune

Explanation:

Weight is mass times gravity. The greater the gravity, the greater the weight.

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Two boats start together and race across a 48-km-wide lake and back. boat a goes across at 48 km/h and returns at 48 km/h. boat

jolli1 [7]

Answer:

Time required by boat 1 for the round trip is less than that of boat 2.

Hence, boat 1 wins.

Explanation:

Case 1: Boat 1

Speed of boat = $\frac{distance of river}{time}$

time = $\frac{distance of river}{speed of boat}$

While going to another end

time = $\frac{distance of river}{speed of boat}$

time = $\frac{48}{48}$

time = 1 hour

While going back,

time = $\frac{distance of river}{speed of boat}$

time = $\frac{48}{48}$

time = 1 hour

Total time taken by boat 1 is,

Total time by boat 1 = 1 hour + 1 hour = 2 hour

Total time by boat 1 = 2 hour

Total time taken by boat 1 for the round trip is 2 hour.

Case 2: Boat 2

Speed of boat = $\frac{distance of river}{time}$

time = $\frac{distance of river}{speed of boat}$

While going to another end

time = $\frac{distance of river}{speed of boat}$

time = $\frac{48}{24}$

time = 2 hour

While going back,

time = $\frac{distance of river}{speed of boat}$

time = $\frac{48}{72}$

time = 0.66 hour

Total time taken by boat 2 is,

Total time by boat 1 = 2 hour + 0.66 hour

Total time by boat 1 = 2.66 hour

Total time taken by boat 2 for the round trip is 2.66 hour.

Time required by boat 1 for the round trip is less than that of boat 2.

Hence, boat 1 wins.

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3 years ago

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Aleonysh [2.5K]

Answer:

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3 years ago

Which statement is true about gravitational forces?

Readme [11.4K]

Hey there!

Your correct answer would be (<span>Every mass exerts a gravitational force on every other mass.) It really doesn't matter the size in mass what so ever, gravity is stronger than mass, mass in nothing compared to mass. Therefor, gravity exert's mass on any object with any size of mass.

Your correct answer would be . . .

</span> $\boxed{\boxed{Every \ mass \ exerts \ a \ gravitational \ force \ on \ every \ other \ mass}}$
<span>
Hope this helps.
~Jurgen</span>

6 0

3 years ago

Read 2 more answers

Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s.

rjkz [21]

Answer:

Momentum of block B after collision = $-50\ kg\ ms^{-1}$

Explanation:

Given

Before collision:

Momentum of block A = $p_{A1}$ = $-100\ kg\ ms^{-1}$

Momentum of block B = $p_{B1}$ = $-150\ kg\ ms^{-1}$

After collision:

Momentum of block A = $p_{A2}$ = $-200\ kg\ ms^{-1}$

Applying law of conservation of momentum to find momentum of block B after collision $p_{B2}$ .

$p_{A1}+p_{B1}=p_{A2}+p_{B2}$

Plugging in the given values and simplifying.

$-100-150=-200+p_{B2}$

$-250=-200+p_{B2}$

Adding 200 to both sides.

$200-250=-200+p_{B2}+200$

$-50=p_{B2}$

∴ $p_{B2}=-50\ kg\ ms^{-1}$

Momentum of block B after collision = $-50\ kg\ ms^{-1}$

6 0

3 years ago

Two cylinders A&B at the same temperature contains the same quantity of the same kind of gas. Cylinder A has three times the

GREYUIT [131]

Answer:

pressure in cylinder A must be one third of pressure in cylinder B

Explanation:

We are told that the temperature and quantity of the gases in the 2 cylinders are same.

Thus, number of moles and temperature will be the same for both cylinders.

To this effect we will use the formula for ideal gas equation which is;

PV = nRT

Where;

P is prrssure

V is volume

n is number of moles

T is temperature

R is gas constant

We are told that Cylinder A has three times the volume of cylinder .

Thus;

V_a = 3V_b

For cylinder A;

Pressure = P_a

Volume = 3V_b

Number of moles = n

Thus;

P_a × 3V_b = nRT

For cylinder B;

Pressure = P_b

Volume = V_b

Number of moles = n

Thus,

P_b × V_b = nRT

Combining the equations for both cylinders, we have;

P_a × 3V_b = P_b × V_b

V_b will cancel out to give;

3P_a = P_b

Divide both sides by 3 to get;

P_a = ⅓P_b

Thus, pressure in cylinder A must be one third of pressure in cylinder B

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3 years ago