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kodGreya [7K]
3 years ago
9

This table shows the acceleration due to gravity on four planets. Planet Gravity (m/s2) Earth 9.8 Mercury 3.7 Neptune 11.2 Uranu

s 8.9 A person would have a different weight on each planet. Arrange the planets in increasing order based on a person’s weight on the planet. Mercury Neptune Earth Uranus < <
Physics
2 answers:
son4ous [18]3 years ago
6 0

Answer:

\Large \boxed{\mathrm{Mercury, \ Uranus, \ Earth, \ Neptune}}

Explanation:

Earth ⇒ 9.8 m/s²

Mercury ⇒ 3.7 m/s²

Neptune ⇒ 11.2 m/s²

Uranus ⇒ 8.9 m/s²

W=m \times g

\sf {Weight=mass \times acceleration \ due \ to \ gravity}

The weight of a person can differ on different planets, but the mass stays the same. The greater the acceleration due to gravity, the greater the weight.

Arranging the planets in increasing order based on a person’s weight on the planet:

Mercury, Uranus, Earth, Neptune

arsen [322]3 years ago
3 0

Answer:

Mercury, Uranus, Earth, Neptune

Explanation:

Weight is mass times gravity.  The greater the gravity, the greater the weight.

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It's greatest at the positive terminal of the battery or power supply.


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State coulomb's law mathematically
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Coulomb's law is express as:

\begin{gathered} F=k\frac{q_1q_2}{r^2} \\ \text{ where} \\ k\text{ is Coulomb's constant} \\ q_1\text{ and }q_2\text{ are the charges} \\ r\text{ is the distance between charges} \end{gathered}

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3 0
2 years ago
If the man on the left pulls on the object with a force of 500 N and the man on the right pulls on the object with a force of 75
Igoryamba
Force is a vector quantity
so pulling from opposite side will be negative
so
750+(-500)= 250N
C is the right answer
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3 0
3 years ago
A heavy ball with a weight of 150 N is hung from the ceiling of a lecture hall on a 4.1-m-long rope. The ball is pulled to one s
AlladinOne [14]

Answer:

The tension in the rope is 262.88 N

Explanation:

Given:

Weight W = 150 N

Length of rope r = 4.1 m

Initial speed of ball v = 5.5 \frac{m}{s}

For finding the tension in the rope,

First find the mass of rod,

mg = 150                          ( g = 9.8 \frac{m}{s^{2} } )

  m = \frac{150}{9.8}

  m = 15.3 kg

Tension in the rope is,

  T = mg + \frac{mv^{2} }{r}

  T = 150 + \frac{15.3 \times (5.5)^{2} }{4.1}

  T = 262.88 N

Therefore, the tension in the rope is 262.88 N

7 0
3 years ago
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