1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Basile [38]
3 years ago
14

Pepper is trying to determine the density of her gold ring. The ring’s mass is 100 grams and the volume displaced by the ring is

5 milliliters.
Chemistry
1 answer:
defon3 years ago
5 0

Answer:

50

Explanation:

You might be interested in
Megan experimented with growing mold. She took 3 pieces of bread from the same loaf and placed each into a plastic sandwich bag.
kvasek [131]

Answer:

Yes, because the light was the manipulated variable

Explanation:

3 0
3 years ago
Read 2 more answers
The image below shows how wolves and dogs compare to some other animals in the levels of classification.
Mariana [72]
Insects and dogs are both in the Animalia classification.
8 0
3 years ago
How many joules of kinetic energy does the pendulum have when it has 50 J of potential energy?
dalvyx [7]

Answer:

...

Explanation:

4 0
3 years ago
Which metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)?
DerKrebs [107]
Correct Answer: option <span>(1) Mn(s)

Reason: 
The </span><span>spontaneity of electrochemical cell, depends on the it's Eo value. Electrochemical cells with positve Eo are spontanous and vice-versa.
</span>
In present case, the  Eo of half-cell of interest are as follows:
Eo Zn2+/Zn = <span>-0.763v
</span>Eo Mg2+/Mg = 2.37v
Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn
                                                                                =  -0.763 - (-1.18)
                                                                                = 0.417v

On other hand, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn
                                                                                =  -2.37 - (-1.18)
                                                                                = -1.19v

Thus, Mn(s) <span>metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)</span>
8 0
3 years ago
The atomic radius of a gold atom is 144×10^-12. The volume of a gold atom can be calculated using the volume of a sphere. The de
Alekssandra [29.7K]
Given:
Atomic radius of gold = 144 x 10⁻¹² m = 144 pm 
Density of gold = 19.3 g/cm³ = 19.3 x 10⁻³ kg/cm³
Mass of gold sample = 1.40 g = 1.4 x 10⁻³ kg

Calculate the volume of an atom. 
v = [(4π)/3]*(144 x 10⁻¹² m)³ = 1.2508 x 10⁻²⁹ m³

Calculate the mass of an atom.
m=(1.2508\tmes10^{-29}\,m^{3})*(19.3\times 10^{-3}\, \frac{kg}{cm^{3}} )*(10^{2}\, \frac{cm}{m})^{3} \\ = 2.4142 \times 10^{-25}  \, kg

Calculate the number of atoms in a sample of mass 1.40 g.
N =  \frac{1.40 \time 10^{-3} kg}{2.4142 \times 10^{-25} \,  \frac{kg}{atom} } =5.8 \times 10^{21} \, atoms

Answer:  5.8 x 10²¹ atoms
3 0
3 years ago
Other questions:
  • Compare and contrast chemical change and physical change.
    6·1 answer
  • Design a synthesis of 2-ethoxy-2-methylpropane from 2-methylpropene.
    13·1 answer
  • What is one characteristic of a sample of matter that indicates it is a pure substance?
    9·2 answers
  • Stained glass consists of colored dyes mixed with silicon dioxide molecules. Variations in the color of the glass occur because
    10·1 answer
  • The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens
    15·1 answer
  • Use Boyle’s law to complete the following:
    9·1 answer
  • What kind of matter is smoke?
    10·2 answers
  • 1. What are the characteristics of a gas?
    5·1 answer
  • Balanced Equation:<br> C3H,OH,) + __02 - __CO2 +<br> H20
    12·1 answer
  • Write the balanced chemical equation for the dissociation reaction of thiosulfuric acid.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!