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Anuta_ua [19.1K]
3 years ago
7

If two objects have different temperatures which direction will heat move for how long

Chemistry
1 answer:
Komok [63]3 years ago
7 0
Heat always flows from hot to cold.
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Which of the following statements is not a description of neptune?
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Neptune has four rings which circle the planet. The rings are made of dust particles, similar to the rings of Saturn.
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What element are usually shiny , can be bent or stretched and conduct electricity
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Convert 86,750,000,000 to scientific notation
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8.675 *10^10

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2. The reaction of zinc with nitric acid was carried out in a calorimeter. This reaction caused the temperature
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Q ≈ 2.26 × 10⁴ J or 22.6 kJ (three significant figures).

3 0
3 years ago
If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density
adelina 88 [10]

Explanation:

The given data is as follows.

      Mass = 27.9 g/mol

As we know that according to Avogadro's number there are 6.023 \times 10^{26} atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

            1 atoms weight = \frac{38}{6.023 \times 10^{26}}    

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

            = \frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}

            = 37.06 \times 10^{-26}

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

                   = a^{3}

                   = (0.503 \times 10^{-9})^{3}

                   = 0.127 \times 10^{-27} m^{3}

Formula to calculate density of diamond cell is as follows.

               Density = \frac{mass}{volume}

                             = \frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}

                            = 2918.1 g/m^{3}

or,                         = 0.0029 g/cc       (as 1 m^{3} = 10^{6} cm^{3})

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

4 0
3 years ago
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