Answer:
B. oxygen and glucose
Explanation:
Oxygen for respiration and glucose for energy utilization
The earth has enough gravity to do that
Answer:
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
Explanation:
One colligative property is the freezing point depression due the addition of a solute. The equation is:
ΔT=Kf*m*i
<em>Where ΔT is change in temperature = 0.400°C</em>
<em>Kf is freezing point constant of the solvent = 1.86°C/m</em>
<em>m is molality of the solution (Moles of solute / kg of solvent)</em>
<em>And i is Van't Hoff constant (1 for a nonelectrolyte)</em>
Replacing:
0.400°C =1.86°C/m*m*1
0.400°C / 1.86°C/m*1 = 0.215m
As mass of solvent is 280.0g = 0.2800kg, the moles of the solute are:
0.2800kg * (0.215moles / 1kg) = 0.0602 moles of solute must be added.
The mass of ethylene glycol must be added is:
0.0602 moles * (62.10g / mol) =
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
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H2O
This equation is a double displacement reaction, and it forms H2CO3, which is very unstable and separates into H2O and CO2.
Answer:
The temperature of the gas after it is filled is 596 K
Explanation:
According to Gay-Lussac law, the pressure of a gas mass is directly proportional to temperature to a constant volume. That means than if pressure rise, the temperature too. We can assume then the volume is constant because the tank is isolated. The tank will be full when pressure will be in equilibrium, that means when pressure will be 1 atm because it is environment pressure. Using the following equation:
P1 /T1 = P2 /T2 and replacing, T2 = P2 *T1 / P1 = 1 atm * 298K / 0.5 atm = 596 K.
I hope my answer helps you
