Answer:
Following are the complete balance of the given equation:
Explanation:
Given equation:
After Balancing the equation:
In the above equation, when the 3 mol Copper sulfate reacts with 2 mol lithium phosphate
, it will produce 2 mol Copper phosphate and 3 mol Lithium sulfate
.
Answer:
Explanation:
Percent composition of sodium chloride .
NaCl
Mol weight = 23 + 35.5 = 58.5 g
58.5 g of NaCl contains 23 g of Na
100 g of NaCl contains 23 x 100 / 58.5 g of Na
= 39.3 %
Na = 39.3 %
58.5 g of NaCl contains 35.5 g of Cl
100 g of NaCl contains 35.5 x 100 / 58.5 g of Na
= 60.7 %
Cl = 60.7 % .
Answer:
The product is cyclohexanol
Explanation:
Firstly,
A ketone undergo a borohydride reduction reaction to form an alcohol as below,
R-CO-R' ⇒ R-CO(OH)-R'
- IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
- From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
- Check with other spectroscopic properties,
- 3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-<u>C</u>H₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-<u>C</u>H₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-<u>C</u>H(CH₂-)-OH).
1.56 δ (4H, triplet) - (-C<u>H</u>₂-CH₂-CH-OH) ; triplet as coupling with 2 H,
1.78 δ (4H, multiplet) - (-CH₂-C<u>H</u>₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH
3.24 δ (1H, quintet); - (-CH₂-CH₂-C<u>H</u>(CH₂-)-OH), coupling with4 H of 2 group of CH₂
3.58 δ (1H, singlet); - (-CH₂-CH₂-CH(CH₂-)-O<u>H</u>), hydrogen of alcohol group, not tend to coupling with other hydrogen
Mass of calcium carbonate (in grams) can be dissolved by 4.1 g of Hcl is 5.62g.
<h3>What is balanced equation?</h3>
A balanced equation is one for a chemical reaction in which the overall charge and the number of atoms for each component are the same for both the reactants and the products. In other words, the mass and charge of both sides of the reaction are equal.
The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,
CaCO₃ + 2HCl --> CaCl₂ + H₂O + CO₂
Hydrochloric acid has a molecular weight of 36.45 g/mol compared to calcium carbonate's molecular weight of 100 g/mol. According to the equation above, 72.9 g of hydrochloric acid may dissolve 100 g of calcium carbonate.
x = (4.1 g HCl)(100 g CaCO3 / 72.9 HCl)
x = 5.62 g.
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The process in which a gaseous substance is converted into a condensed, more usable chemical substance is called fixation