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vovangra [49]
2 years ago
6

For green plant cells, which are the substances that result from photosynthesis that are used in cellular respiration? A. oxygen

and water B. oxygen and glucose C. carbon dioxide and water D. carbon dioxide and glucose
Chemistry
1 answer:
strojnjashka [21]2 years ago
6 0

Answer:

B. oxygen and glucose

Explanation:

Oxygen for respiration and glucose for energy utilization

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What is the energy of an object because of its potential and kinetic energies?
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Answer:

The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy

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Please select the word from the list that best fits the definition
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Systemic Circulation

Explanation:

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In many species, a transition metal has an unusually high or low oxidation state. Write balanced equations for the following and
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When `CO_(2)` is bubbled through a cold pasty solution of barium peroxide in water, `H_(2)O_(2)` is obtained. <br> `BaO+CO_(2)+H_(2)OtoBaCO_(3)+H_(2)O_(2)` Barium carbonate being insoluble is filtered off. This is known as Merck's process.

<h3>What is meant by Perhydrol?</h3>

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7 0
1 year ago
The equation shows lead reacting with sulfuric acid to produce lead sulfate and hydrogen gas.
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This equation represents a single replacement reaction. Single replacement reactions consist of one element reacting with one compound on the reactant side (left side of the equation) and they form one new element and one new compound on the product side of the equation (right side).
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3 years ago
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The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?
Phoenix [80]
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
         mass        moles
C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
2 years ago
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