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vovangra [49]
3 years ago
6

For green plant cells, which are the substances that result from photosynthesis that are used in cellular respiration? A. oxygen

and water B. oxygen and glucose C. carbon dioxide and water D. carbon dioxide and glucose
Chemistry
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

B. oxygen and glucose

Explanation:

Oxygen for respiration and glucose for energy utilization

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Which of the following natural resources cant be reused
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Hi there! Air and sunlight can definitely be reused. Those are abundant and renewable resources. Therefore, A and D are eliminated. There is a limited amount of water, however, it's impossible to run out of it to the point that there's no more on Earth. C is out. The only answer choice that makes sense is coal, because it's a nonrenewable resource, and it takes millions of years to make more of. It's a fossil fuel, so once we use them up, we can't get anymore during our lives. The answer is B: coal.
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PLEASE ANSWER ASAP NEED ANSWER!!!!!!!!!!!!!! 75 POINTS
kakasveta [241]

Answer:

The answer to your question is A.

Pure substances can not be broken down into others, so they cannot be molecules

Explanation:

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2 years ago
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Which of the following is not conserved in a chemical reaction?
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Mass is not conserved in chemical reactions. Mass is therefore never conserved because a little of it turns into energy in every reaction
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What kind of liquid promote corrosion
MaRussiya [10]
Is this the whole answer?
7 0
3 years ago
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
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