5.0=mo(1/2) ^ 5
5.0=mo (.031)
about 160/161.29
That would be convection. This is a test. ;)
Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
<h3>What is heat of reaction?</h3>
The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.
According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.
Molar mass of ammonia = 17 g
Mass of 4 moles of ammonia = 4 × 17 = 68 g
1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.
Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
Learn more about enthalpy at: brainly.com/question/14047927
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Answer:
547 L of water vapour
Explanation:
Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20
From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.
Molar mass of gypsum = 172 g/mol
Molar mass of H2O = 18 g/mol
Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour
i.e. 344 g of gypsum produces 54 g of H2O
2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.
Volume of water vapour produced = mass/density
Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour
Therefore 547 L of water vapour are produced
Answer:
O=O bond
Explanation:-
Note it down that the bond having highest Hydrogen enthalpy has strongest bond.
Now
- O=O(495KJ/mol)
- O-O(146KJ/mol)
- O-H(467KJ/mol)
- H-H(432KJ/mol)
Hence
