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Gala2k [10]
3 years ago
10

A quantity of gas in a piston cylinder has a volume of .362M3(cubed. If the gas is initially at room temperature (20C) and is he

ated in isometric process, what will be the temp. In degrees Celsius when it expanded to a volume of .632m3 (cubed
Physics
1 answer:
Sav [38]3 years ago
6 0

The final temperature is 34.91°C

<u>Explanation:</u>

<u></u>

Initial volume, V1 = 362m³

Final volume, V2 = 632m³

Initial temperature, T1 = 20°C

Final temperature, T2 = ?

We know,

V1/T1 = V2/T2

362/20 = 632/T2

T2 = 34.91°C

Therefore, the final temperature is 34.91°C

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Answer:

9.31%

Explanation:

We are given that

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Volume of solution=473 mL

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Mass =volume\times density

Using the formula

Mass of solution=1.12\times 473=529.76 g

Mass % of KBr=\frac{mass\;of\;KBr}{Total\;mass\;of\;solution}\times 100

Mass % of KBr=\frac{49.3}{529.76}\times 100

Mass % of KBr=9.31%

Hence, the mass% of KBr=9.31%

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