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klio [65]
3 years ago
13

In vision, the amplitude of a light wave relates to people's perception of the brightness of a stimulus. To which perceptual dim

ension does the amplitude of a sound wave correspond in hearing?
Physics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

Loudness

Explanation:

In acoustics, loudness is the subjective perception of sound pressure.

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BI
Charra [1.4K]

Answer: A

Explanation:

8 0
3 years ago
what is the value of the constant for a second order reaction if the reactant concentration drops from .657 M to ,0981 M in 17 s
yaroslaw [1]

Answer : The value of the constant for a second order reaction is, 0.51M^{-1}s^{-1}

Explanation :

The expression used for second order kinetics is:

kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}

where,

k = rate constant = ?

t = time = 17s

[A_t] = final concentration = 0.0981 M

[A_o] = initial concentration = 0.657 M

Now put all the given values in the above expression, we get:

k\times 17s=\frac{1}{0.0981M}-\frac{1}{0.657M}

k=0.51M^{-1}s^{-1}

Therefore, the value of the constant for a second order reaction is, 0.51M^{-1}s^{-1}

6 0
3 years ago
Photoelectrons with a maximum speed of 8.00 • 106 m/sec are ejected froma surface in the presence of light with a frequency of 6
Andru [333]

The kinetic energy is given by:

K=\frac{1}{2}mv^2

We know the mass and the maximum speed, plugging their values in the expression above we have:

\begin{gathered} K=\frac{1}{2}(9.1\times10^{-31})(8\times10^6)^2 \\ K=2.91\times10^{-17}\text{ J} \end{gathered}

Therefore, the answer is d.

5 0
1 year ago
The glass in a window is 35 inches wide and 20 inches tall, and standard atmospheric pressure is 14.7 pounds per square inch. Wh
iogann1982 [59]

Answer:103 pounds

Explanation:

Given

width of window b=35 in.

height of window h=20 in.

standard atmospheric pressure P_{outside}=14.7 psi

Also P_{inside}=1.01P_{outside}

Thus Net Force on the window will be the algebraic sum of Force due to outside and inside Pressure .

F_{net}=(P_{inside}-P_{outside})\cdot A

F_{net}=P_{outside}(1.01-1)\times 35\times 20

F_{net}=14.7\times 0.01\times 35\times 20

F_{net}=102.9\ pounds\approx 103\ pounds            

8 0
3 years ago
Can I also get help on this??
Xelga [282]

Answer:

25

Explanation:

8 0
3 years ago
Read 2 more answers
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