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kkurt [141]
4 years ago
7

 Will mark as Brainliest!! If possible, Please check these!!! Quiz and I need to pass!!! If you see anything wrong from my answe

rs, please let me know!! Give points for it!!!
5.09 Quiz: How Heat Moves

Question One: What are the ways that heat moves?

A) Heat only moves through conduction and radiation.

B) Heat moves through conduction, convection, and radiation.

C) Heat only moves through air currents.

D) Heat moves from a cold object to a warm object.

Answer I chose was B.

Question two: Convection requires______to transfer heat.

A) solids

B) fluids (liquids or gases)

C) insulation

D) the vacuum of space

Answer I chose was C.

Question three: What does an insulator do?

A) An insulator emits elctromagnetic radiation.

B) An insulator slows heat transfer.

C) An insulator cools a substance.

D) An insulator warms a substance.

Answer I chose was B.

Please check and/or answer!!

~Karleif Westsson
Physics
2 answers:
jarptica [38.1K]4 years ago
5 0
I think everything looks good but 2 might not be right, it might be B
m_a_m_a [10]4 years ago
5 0

#1). correct

#2). B.  Convection is the process of hot and cold fluids FLOWING up and down, carrying heat from place to place that way.  That means there's gotta be some gas or liquid to flow from place to place, else you gotta no convection.

#3). correct


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A fan at a rock concert is 50.0 m from the stage, and at this point the sound intensity level is 114 dB. Sound is detected when
Marianna [84]

Answer:

A) P=13.92\ J.s^{-1}

B) v=3730.9912\ m.s^{-1}

C) v=74.44\ mm.s^{-1}

D) mosquitoes speed in part B is very much larger than that of part C.

Explanation:

Given:

  • Distance form the sound source, s=50\ m
  • sound intensity level at the given location, \beta=114\ dB
  • diameter of the eardrum membrane in humans, d=8.4 \times 10^{-3}\ m
  • We have the minimum detectable intensity to the human ears, I_0=10^{-12}\ W.m^{-2}

(A)

<u>Now the intensity of the sound at the given location is related mathematically as:</u>

\beta=10\ log(\frac{I}{I_0} ) ..........................................(1)

114=10\ log\ (\frac{I}{10^{-12}} )

11.4=log\ I+12\ log\ 10

I=0.2512\ W.m^{-2}

<em>As we know :</em>

I=\frac{P}{A}

0.2512=\frac{P}{\pi\times \frac{8.4^2}{4} }

P=13.92\ J.s^{-1} is the energy transferred to the  eardrums per second.

(B)

mass of mosquito, m=2\times 10^{-6}\ kg

<u>Now the velocity of mosquito for the same kinetic energy:</u>

KE=\frac{1}{2} m.v^2

13.92=\frac{1}{2}\times 2\times 10^{-6}\times v^2

v=3730.9912\ m.s^{-1}

(C)

Given:

  • Sound intensity, \beta = 20\ dB

<u>Using eq. (1)</u>

20=10\ log\ (\frac{I}{10^{-12}} )

2=log\ I+12\ log\ 10

I=10^{-10}\ W.m^{-2}

Now, power:

P=I.A

P=10^{-10}\times \pi\times \frac{8.4^2}{4}

P=5.54\times 10^{-9}\ J.s^{-1}

Hence:

KE=\frac{1}{2} m.v^2

5.54\times 10^{-9}=0.5\times 2\times 10^{-6}\times v^2

v=0.07444\ m.s^{-1}

v=74.44\ mm.s^{-1}

(D)

mosquitoes speed in part B is very much larger than that of part C.

7 0
4 years ago
In a periodic table, dots around an elements symbol indicate the number of valence electrons in an atom ? True Or False
gavmur [86]
I would probally say  true? I am not positive

5 0
3 years ago
Read 2 more answers
What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second?
Alexus [3.1K]

Given:-

  • Mass of the cart (m) = 35 kg
  • Speed (consider Velocity) = 1.2 m/s

To Find: Momentum of the cart.

We know,

p = mv

where,

  • p = Momentum,
  • m = Mass &
  • v = Velocity.

Thus,

p = (35 kg)(1.2 m/s)

→ p = 42 kg m/s (Ans.)

Conclusion:-

A. ☑️ 42 kilogram - metre per second.

6 0
3 years ago
The wavelength of a wave on a string is 1.2 meters. If the speed of the wave is 60 meters/second, what is its frequency?
maria [59]
F=v/wavelength f=1.2/60=50Hz.
8 0
3 years ago
Read 2 more answers
Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .
soldi70 [24.7K]

Answer:

4.0932672025\times 10^{-17}

Explanation:

E_a = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

f=e^{-\dfrac{E_a}{RT}}\\\Rightarrow f=e^{-\dfrac{160000}{8.314\times 510}}\\\Rightarrow f=4.0932672025\times 10^{-17}

The fraction of energy is 4.0932672025\times 10^{-17}

3 0
3 years ago
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